To calculate the probability of winning both games, given that the events are independent, we multiply the individual probabilities:

$P(\text{Win both games}) = P(\text{Win first game}) \times P(\text{Win second game})$

Given:

• $P(\text{Win first game}) = 0.35$
• $P(\text{Win second game}) = 0.16$

Now, we perform the multiplication:

$P(\text{Win both games}) = 0.35 \times 0.16 = 0.056$

Thus, the probability of winning both games is:

$\boxed{0.056} \text{ or } 5.6\%$

Would you like to see further details or have any questions?

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Here are 5 related questions:

1. What is the probability of winning at least one of the two games?
2. What is the probability of winning only the first game?
3. What is the probability of winning only the second game?
4. How would the probability change if the two games were not independent?
5. What is the probability of losing both games?

Tip: When working with independent events, always multiply the individual probabilities for "AND" scenarios.