You play two unrelated games one after the other, there is a 35% chance of winning the first game and there is a 16% chance of winning the second game. What is the probability that you win both games? 

To calculate the probability of winning both games, given that the events are independent, we multiply the individual probabilities:

\[
P(\text{Win both games}) = P(\text{Win first game}) \times P(\text{Win second game})
\]

Given:
- \( P(\text{Win first game}) = 0.35 \)
- \( P(\text{Win second game}) = 0.16 \)

Now, we perform the multiplication:

\[
P(\text{Win both games}) = 0.35 \times 0.16 = 0.056
\]

Thus, the probability of winning both games is:

\[
\boxed{0.056} \text{ or } 5.6\%
\]

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Here are 5 related questions:
1. What is the probability of winning at least one of the two games?
2. What is the probability of winning only the first game?
3. What is the probability of winning only the second game?
4. How would the probability change if the two games were not independent?
5. What is the probability of losing both games?

**Tip:** When working with independent events, always multiply the individual probabilities for "AND" scenarios.

You play two unrelated games one after the other, there is a 35% chance of winning the first game and there is a 16% chance of winning the second game. What is the probability that you win both games?

Calculate the probability of winning two independent games with 35% and 16% win chances, respectively. This solution covers probability concepts for independent events, including the multiplication rule. Suitable for students in Grades 10-12.

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