Math Problem Statement

In a​ lottery, the top cash prize was ​$672 ​million, going to three lucky winners. Players pick five different numbers from 1 to 55 and one number from 1 to 49. A player wins a minimum award of $ 100 by correctly matching two numbers drawn from the white balls​ (1 through 55​) and matching the number on the gold ball​ (1 through 49​). What is the probability of winning the minimum​ award in a fraction?

i

Solution

To find the probability of winning the minimum award in the lottery, we need to calculate two separate probabilities:

  1. Probability of matching exactly two numbers from the five white balls (out of 55).
  2. Probability of matching the one gold ball (out of 49).

Step 1: Total number of ways to choose white balls

The total number of ways to choose 5 white balls from 55 is given by the combination formula: (555)=55!5!(555)!\binom{55}{5} = \frac{55!}{5!(55-5)!} Calculating this: (555)=55×54×53×52×515×4×3×2×1=3,478,761\binom{55}{5} = \frac{55 \times 54 \times 53 \times 52 \times 51}{5 \times 4 \times 3 \times 2 \times 1} = 3,478,761 So, there are 3,478,761 ways to choose 5 white balls from 55.

Step 2: Number of ways to match exactly two white balls

The number of ways to match exactly 2 white balls is the combination: (52)=5×42×1=10\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10 Now, for the remaining 3 white balls (that the player doesn't match), they must be chosen from the other 50 white balls (since the player didn't match them). The number of ways to choose these is: (503)=50×49×483×2×1=19,600\binom{50}{3} = \frac{50 \times 49 \times 48}{3 \times 2 \times 1} = 19,600 So, the total number of ways to match exactly 2 white balls and miss 3 others is: 10×19,600=196,00010 \times 19,600 = 196,000

Step 3: Probability of matching the gold ball

Since there is only 1 gold ball to match out of 49, the probability of matching the gold ball is: 149\frac{1}{49}

Step 4: Total number of favorable outcomes

The total number of favorable outcomes is the product of matching 2 white balls and matching the gold ball: 196,000×1=196,000196,000 \times 1 = 196,000

Step 5: Total number of possible outcomes

The total number of possible outcomes (choosing 5 white balls and 1 gold ball) is: 3,478,761×49=170,459,2893,478,761 \times 49 = 170,459,289

Step 6: Probability of winning the minimum award

The probability of winning the minimum award is the ratio of favorable outcomes to the total number of outcomes: 196,000170,459,289\frac{196,000}{170,459,289}

So, the probability of winning the minimum award is: 196,000170,459,289\boxed{\frac{196,000}{170,459,289}}

This is the exact probability in fractional form.


Would you like further explanation or have any additional questions?

Here are 5 related questions to explore further:

  1. How do you compute probabilities for matching exactly 3 or 4 white balls?
  2. What is the probability of not matching any numbers in this lottery?
  3. How does the probability change if the pool of white balls increases to 60?
  4. What is the probability of matching only the gold ball and no white balls?
  5. How would you calculate the expected value of a lottery ticket in this scenario?

Tip: When calculating combinations, using a scientific calculator or programming tool can help avoid errors in large factorials!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Combinatorics

Formulas

Combination formula: C(n, k) = n! / [k!(n-k)!]
Probability of matching two white balls: C(5, 2) * C(50, 3)
Probability of matching the gold ball: 1/49

Theorems

Basic Probability Theory
Combinatorial Counting Principles

Suitable Grade Level

Grades 10-12