The problem asks how many times you should expect to get a sum of 6 when tossing a pair of dice 720 times.

To solve this, let's first determine the probability of rolling a sum of 6.

The possible ways to get a sum of 6 when rolling two dice are:

• (1, 5)
• (2, 4)
• (3, 3)
• (4, 2)
• (5, 1)

So, there are 5 outcomes where the sum is 6. The total number of possible outcomes when rolling two dice is 6 * 6 = 36, since each die has 6 faces.

Therefore, the probability $P$ of rolling a sum of 6 is:

$P = \frac{5}{36}$

Now, if we toss the pair of dice 720 times, the expected number of times we get a sum of 6 is:

$\text{Expected number} = 720 \times P = 720 \times \frac{5}{36}$

Let's calculate that:

$\text{Expected number} = 720 \times \frac{5}{36} = 100$

Thus, you should expect to get a sum of 6 approximately 100 times in 720 rolls.

Let me know if you'd like any further details or if you have additional questions!

Here are a few related questions:

1. What are the other probabilities for different sums when rolling two dice?
2. How does the probability change if we roll a different number of dice?
3. How can we calculate the probability of rolling a sum of 7 or 8?
4. What is the expected number of times we get a sum of 7 in 720 rolls?
5. How can we use probability theory to predict the outcomes of other games of chance?

Tip: When working with probability, always make sure to first list all possible outcomes before calculating.