To find the probability that a student was male and got a "B," we will use the formula for probability:

$P(\text{male and "B"}) = \frac{\text{Number of males who got a "B"}}{\text{Total number of students}}$

Step-by-Step Solution:

1. Number of males who got a "B" = 15
2. Total number of students = 49

So, the probability is:

$P(\text{male and "B"}) = \frac{15}{49}$

The fraction $\frac{15}{49}$ is already in its simplest form, so the final answer is:

$P(\text{male and "B"}) = \frac{15}{49}$

Would you like further details, or do you have any questions?

Here are five related questions to explore:

1. What is the probability of selecting a student who is female and got a "C"?
2. What is the probability that a student got a grade of "A"?
3. If a student is chosen randomly, what is the probability that the student is male?
4. What is the probability that a student chosen randomly got a "B"?
5. What is the probability that a student chosen at random is female?

Tip: When dealing with probability, always ensure fractions are reduced to their simplest form to make interpretation easier.