To solve this problem, let's calculate the probability that Yeshey picks a local product (which is the product "Jumpy").

Step 1: Find the Total Number of Juices

The total number of juices in the bag can be found by adding up all the different types:

• Appy: 2
• Jumpy: 3
• Litchi: 4
• Lipton: 6

Thus, the total number of juices is:

$2 + 3 + 4 + 6 = 15$

Step 2: Determine the Number of Local Products

The local product is "Jumpy," and there are 3 of them. Therefore:

$\text{Number of local products} = 3$

Step 3: Calculate the Probability

The probability of picking a local product is given by the ratio of the number of local products to the total number of products. Thus:

$P(\text{local product}) = \frac{\text{Number of local products}}{\text{Total number of juices}} = \frac{3}{15} = \frac{1}{5}$

Final Answer

The probability that Yeshey picks a local product is:

$\boxed{\frac{1}{5}}$

Would you like more details or do you have any questions?

Here are 5 relative questions to expand on this topic:

1. What is the probability of selecting an imported product from the bag?
2. If Yeshey picks two juices at random without replacement, what is the probability that both are local?
3. How would the probability change if there were 5 Jumpy juices instead of 3?
4. What is the probability of picking a Lipton juice from the bag?
5. How would we calculate the expected value of the number of local products if we repeatedly pick from the bag?

Tip: When calculating probability, always ensure you correctly identify the favorable outcomes and the total possible outcomes.