To find the probability of getting 6 or more girls in 8 births, we need to sum the probabilities from the distribution for $x \geq 6$.

From the table:

• $P(6) = 0.115$
• $P(7) = 0.026$
• $P(8) = 0.001$

The probability of getting 6 or more girls is:

$P(X \geq 6) = P(6) + P(7) + P(8)$

Substituting the values:

$P(X \geq 6) = 0.115 + 0.026 + 0.001 = 0.142$

So, the probability of getting 6 or more girls in 8 births is 0.142.

Would you like more details or have any questions?

Related Questions:

1. What is the probability of getting exactly 5 girls in 8 births?
2. How do we calculate the expected number of girls in 8 births from this distribution?
3. What is the variance of the number of girls in 8 births?
4. How would the probability change if the total number of births were different?
5. Can we determine if the distribution follows a binomial pattern?

Tip:

When working with probability distributions, always ensure the sum of all probabilities equals 1 to validate the distribution's correctness.