A fair coin is tossed four times. What is the probability that the sequence of tosses is TTTT? Write your answer as a fraction or a decimal, rounded to four decimal places.

Each toss of a fair coin has two possible outcomes: heads (H) or tails (T). The probability of getting a tail (T) on any single toss is \( \frac{1}{2} \).

Since the tosses are independent of each other, the probability of getting four tails in a row (TTTT) is the product of the probabilities for each individual toss. That is:

\[
P(TTTT) = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{16}
\]

Expressing this as a decimal:

\[
\frac{1}{16} = 0.0625
\]

Thus, the probability that the sequence of tosses is TTTT is \( 0.0625 \).

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Here are 5 related questions:
1. What is the probability of getting exactly two tails in four coin tosses?
2. How many possible outcomes are there when a coin is tossed four times?
3. What is the probability of getting at least one head in four tosses?
4. If the coin is biased with a 60% chance of landing heads, what is the probability of TTTT?
5. What is the probability of getting the sequence HHTT?

**Tip:** When calculating probabilities for independent events, multiply the individual probabilities of each event.

Explore the probability of getting four tails (TTTT) in a sequence of four coin tosses. This problem demonstrates key concepts in probability and the multiplication rule for independent events. Suitable for students in Grades 5-7.

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