Each toss of a fair coin has two possible outcomes: heads (H) or tails (T). The probability of getting a tail (T) on any single toss is $\frac{1}{2}$.

Since the tosses are independent of each other, the probability of getting four tails in a row (TTTT) is the product of the probabilities for each individual toss. That is:

$P(TTTT) = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{16}$

Expressing this as a decimal:

$\frac{1}{16} = 0.0625$

Thus, the probability that the sequence of tosses is TTTT is $0.0625$.

Would you like any further details on this problem?

Here are 5 related questions:

1. What is the probability of getting exactly two tails in four coin tosses?
2. How many possible outcomes are there when a coin is tossed four times?
3. What is the probability of getting at least one head in four tosses?
4. If the coin is biased with a 60% chance of landing heads, what is the probability of TTTT?
5. What is the probability of getting the sequence HHTT?

Tip: When calculating probabilities for independent events, multiply the individual probabilities of each event.