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To solve the problem, we need to calculate the probability that all four children in a family are girls.

### Solution:
Each child can either be a girl or a boy. Assuming that the probability of having a girl is \( \frac{1}{2} \) (since it is equally likely to have a boy or a girl), we can use the fact that these events are independent (the gender of one child does not affect the others).

So, the probability of all four children being girls is:
\[
P(\text{all girls}) = \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) = \left( \frac{1}{2} \right)^4 = \frac{1}{16}
\]

Thus, the probability that all four children are girls is \( \frac{1}{16} \).

Do you have any questions, or would you like more details on this? 

Here are five related questions:
1. What is the probability that all four children are boys?
2. What is the probability that exactly two of the four children are girls?
3. How does the probability change if the chance of having a girl is \( \frac{3}{5} \) instead of \( \frac{1}{2} \)?
4. What is the probability of having at least one girl in a family with four children?
5. How would the probability change if the family had five children instead of four?

**Tip:** In probability problems involving independent events, multiplying the probabilities of individual outcomes gives the total probability for a sequence of events.

Given a family with four children, find the probability of the event: All are girls.

Find out how to calculate the probability that all four children in a family are girls. This problem involves calculating the probability of independent events and applying basic probability rules. Perfect for students in Grades 7-9.

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