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The problem asks to find the chance of getting an even number on the 4th roll of a fair six-sided die, given that the first three rolls were odd numbers.

Let's break this down:

### Key points:
- A fair six-sided die has the numbers 1, 2, 3, 4, 5, 6.
- Odd numbers: 1, 3, 5 (3 outcomes).
- Even numbers: 2, 4, 6 (3 outcomes).

The important thing to note is that **the outcome of the first three rolls does not affect the probability of the 4th roll**, because each roll of the dice is an independent event.

### Probability calculation:
- The probability of rolling an even number (2, 4, or 6) on any roll of a six-sided die is:
  \[
  P(\text{even}) = \frac{3}{6} = \frac{1}{2}
  \]

So, the probability of getting an even number on the 4th roll is **\( \frac{1}{2} \)**.

### Conclusion:
The chance of getting an even number on the 4th roll is \( \frac{1}{2} \) or 50%.

Would you like more details or have any other questions?

Here are 5 related questions for further exploration:
1. What is the probability of rolling only even numbers in 4 consecutive rolls?
2. What is the probability of rolling an odd number on the 4th roll after 3 odd numbers?
3. If you rolled 4 dice, what is the probability that exactly 2 of them will be even?
4. How does the probability change if the die has more than 6 sides?
5. What is the probability of rolling a sum greater than 10 after 2 rolls of the die?

**Tip:** In probability, when events are independent, the outcome of one event does not influence the outcomes of others. This is the case with fair dice rolls.

If you get an odd number on each of the first 3 rolls of a fair six-sided dice, find the chance of getting an even number on the 4th throw.

Discover the probability of rolling an even number on the 4th roll of a fair six-sided dice after three odd rolls. This problem highlights key probability concepts, including the independence of dice rolls and calculating chances for even outcomes. Suitable for Grades 6-8.

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