Let's solve this problem.

Given Information:

• The deck consists of 52 cards.
• Half the deck consists of red cards (26 red cards, which are hearts and diamonds).
• Eric draws a red card, places it back, shuffles, and then draws another card.

We need to find:

• The probability of drawing a red card and then drawing another red card.

Solution:

1. Probability of drawing the first red card: Since there are 26 red cards out of 52 total cards, the probability of drawing a red card is: $P(\text{red card}) = \frac{26}{52} = \frac{1}{2}$

2. Probability of drawing the second red card: Since Eric places the card back in the deck and shuffles, the probability of drawing a red card again is still the same: $P(\text{red card}) = \frac{1}{2}$

3. Combined probability of drawing two red cards: The two events are independent (since the card is placed back in the deck), so we multiply the probabilities: $P(\text{two red cards}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = 0.25$ As a percentage, this is: $0.25 \times 100 = 25\%$

Answer:

The probability is 25%.

Do you need more details, or do you have any questions?

Here are 5 related questions:

1. What is the probability of drawing two black cards consecutively?
2. How would the probability change if the card wasn't replaced in the deck?
3. What is the probability of drawing one red card and one black card?
4. What is the probability of drawing two red cards from a deck of 52 without replacement?
5. If the deck has jokers, how would that affect the probability?

Tip: When working with probabilities involving replacement, remember that the events are independent, and the probability of each event remains constant.