Math Problem Statement
Let n be a natural number, and there are a total of (2n+1) cards with the numbers from 0 to 2n written one by one.
A card is taken at random from among these cards, and the number written on it is X.
When Y is determined by (a) and (b) below, let {k| k∈N ,0≤k≤2n} and find the probability P(Y) that Y=k.
(a) If X is odd, then Y= X
(b) If X is an even number containing 0, return the card and take one new card at random from all the cards and let Y be the number written on it.
Solution
To solve the problem, we need to find the probability where is defined based on the conditions (a) and (b) given:
- If (the number on the initially drawn card) is odd, then .
- If is even (including 0), the card is returned and a new card is drawn to determine .
Let's break this down step by step.
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Determine the total number of cards and their values:
There are cards, numbered from 0 to 2n.
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Probability of drawing an odd or even card:
- There are even cards (including 0).
- There are odd cards.
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Initial drawing probabilities:
- Probability of drawing an even number (including 0): .
- Probability of drawing an odd number: .
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Determining when is odd:
If is odd, . There are odd numbers (1, 3, 5, ..., ).
- Probability for an odd :
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Determining when is even:
If is even, we return the card and draw again. In this scenario, is determined purely by the probability of drawing any number from the set , which is equally likely for each number.
- Probability for any :
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Combining both scenarios:
For even :
- can only be the result of drawing again since is even and not initially possible from (a).
For odd :
- can either be from an initial odd draw or from drawing again after returning an even card. Simplifying for odd :
Thus, the probability is:
\frac{1}{2n+1} & \text{if } k \text{ is odd} \\ \frac{n+1}{(2n+1)^2} & \text{if } k \text{ is even} \end{cases}$$ Would you like further details or have any questions on this? Here are five questions you might ask next: 1. How do you compute expected values in probability? 2. Can you explain conditional probability with an example? 3. What is the probability of drawing two specific cards in succession without replacement? 4. How do you find the variance of a probability distribution? 5. What is the law of large numbers? **Tip:** In probability problems, clearly defining each step and condition can simplify finding the solution and avoid confusion.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Probability Theory
Conditional Probability
Formulas
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Theorems
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Suitable Grade Level
Advanced High School or College
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