Math Problem Statement
For a continuous random variable X, P(25 ≤ X ≤ 73) = 0.28 and P(X > 73) = 0.12. Calculate the following probabilities.
Note: Round your answers to 2 decimal places.
P(X < 73) P(X < 25) P(X = 73
Solution
We are given the following probabilities for the continuous random variable :
Step-by-step solution:
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Calculate : The total probability for any continuous random variable is 1. Therefore: Substituting the given probability:
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Calculate : We can break down the probabilities around 25 and 73 as follows: Rearranging this: Substituting the known values:
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Calculate : Since is a continuous random variable, the probability of it taking any exact value is 0. Therefore:
Final answers:
Would you like further details or have any questions?
Related Questions:
- How would you calculate ?
- What is the cumulative distribution function (CDF) based on this data?
- How do you find the probability if the distribution was discrete instead of continuous?
- What if was given, how would that change the calculations?
- How can you use this information to calculate the mean or variance of ?
Tip: For continuous random variables, the probability of an exact value is always zero. This is a key property that distinguishes continuous distributions from discrete ones.
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Math Problem Analysis
Mathematical Concepts
Probability Theory
Continuous Random Variables
Formulas
P(X < 73) = 1 - P(X > 73)
P(X < 25) = 1 - P(25 ≤ X ≤ 73) - P(X > 73)
P(X = 73) = 0 (For continuous variables)
Theorems
Total Probability Theorem
Properties of Continuous Distributions
Suitable Grade Level
Grades 11-12, Early College
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