To find the probability that a baseball pitch is thrown with fewer than two strikes, we'll consider the following:

Key Points:

• There are typically 3 possible strike counts for a pitch: 0 strikes, 1 strike, or 2 strikes.
• The event "fewer than two strikes" includes both 0 strikes and 1 strike.

Let's assume that the probability of each strike count (0, 1, or 2 strikes) is equally likely, so each has a probability of $\frac{1}{3}$.

Step-by-Step Calculation:

1. Event "Fewer than two strikes" includes:

   • 0 strikes
   • 1 strike

2. Probability of fewer than two strikes: $P(\text{Fewer than two strikes}) = P(0 \text{ strikes}) + P(1 \text{ strike})$ $P(\text{Fewer than two strikes}) = \frac{1}{3} + \frac{1}{3} = \frac{2}{3}$

3. Rounding to four decimal places: $P(\text{Fewer than two strikes}) = 0.6667$

Final Answer:

$P(\text{A baseball pitch thrown with fewer than two strikes}) = 0.6667$

Would you like more details or have any questions?

Here are some related questions you might be interested in:

1. What is the probability of getting exactly one strike on a pitch?
2. How does the probability change if the strike counts are not equally likely?
3. What is the probability of a pitch being thrown with exactly two strikes?
4. How do we calculate the probability of getting no strikes at all?
5. What assumptions are made in this probability calculation?

Tip: Always verify if probabilities are equally distributed before calculating. If not, adjust the probabilities accordingly.