To find your chances of getting all the answers correct on the quiz, we need to calculate the probability of answering every individual question correctly, given that you have an 80% chance of answering any individual question correctly.

Step-by-step process:

1. Probability of answering one question correctly = 80% = 0.80.
2. Probability of answering one question incorrectly = 100% - 80% = 20% = 0.20.

Now, for 6 independent multiple-choice questions, you want the probability of getting all 6 questions correct. Since each question is independent, we multiply the probability of getting each question right:

$P(\text{All correct}) = 0.80 \times 0.80 \times 0.80 \times 0.80 \times 0.80 \times 0.80 = 0.80^6$

Calculating that:

$P(\text{All correct}) = 0.262144$

This means there is about a 26.2% chance of getting all the answers correct.

Final answer:

Your chances of getting all the answers correct are 26.2%.

Would you like a deeper breakdown or further examples on this? Here are some related questions:

1. What is the probability of getting at least 5 out of 6 questions correct?
2. How would the probability change if your chance of getting each question correct was 90%?
3. How do you calculate the probability of getting all answers wrong?
4. How does the probability change if you answered 10 questions instead of 6?
5. What is the formula to calculate the probability of getting "n" out of "k" questions correct?

Tip: In problems like this, when you have multiple independent events, the overall probability is the product of the individual probabilities.