Math Problem Statement
A company receives a very large shipment of components. A random sample of 20 of these components will be checked, and the shipment will be accepted if fewer than 2 of these components are defective. What is the probability of accepting a shipment containing 5% defectives?
Solution
This problem can be modeled using the binomial distribution because we have a fixed number of trials (20 components), two possible outcomes for each trial (defective or not defective), and a constant probability of a defective component (5% or 0.05).
Let be the random variable representing the number of defective components in the sample of 20 components. follows a binomial distribution: Where:
- (sample size),
- (probability of a defective component).
The shipment is accepted if fewer than 2 components are defective, meaning we want to find the probability that .
This can be expressed as:
Using the binomial probability formula: Where:
- is the binomial coefficient,
- is the probability of having exactly defective components,
- is the probability of the remaining components being non-defective.
Let's calculate and .
-
For :
-
For :
Let's now compute the final probability.The probability of accepting a shipment containing 5% defectives, by finding fewer than 2 defective components in the random sample of 20, is approximately 0.736 or 73.6%.
Would you like further details or have any other questions? Here are five related questions you might find helpful:
- How would the probability change if the sample size increased to 30 components?
- What happens to the probability if the defective rate increases to 10%?
- How does the binomial distribution change if we allow up to 3 defective components for acceptance?
- Can this problem be solved using a Poisson approximation instead of a binomial distribution?
- How would the company optimize the sample size to minimize the risk of accepting a bad shipment?
Tip: When working with small probabilities and large sample sizes, consider using approximations like the Poisson distribution for efficiency.
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Math Problem Analysis
Mathematical Concepts
Probability
Binomial Distribution
Formulas
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
P(X < 2) = P(X = 0) + P(X = 1)
Theorems
Binomial Theorem
Suitable Grade Level
College/Advanced High School
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