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To find the prime factorization of 45 in exponent form, we need to break it down into its prime factors.

1. Start by dividing 45 by the smallest prime number, which is 3:
   \[
   45 \div 3 = 15
   \]

2. Divide 15 by 3 again:
   \[
   15 \div 3 = 5
   \]

3. Now, 5 is a prime number, so the division stops here.

The prime factors of 45 are \(3\) and \(5\), with \(3\) appearing twice. In exponent form, the prime factorization of 45 is:
\[
45 = 3^2 \times 5^1
\]

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### Related Questions:
1. What is the prime factorization of 60?
2. How do you find the prime factorization of a number?
3. What is the prime factorization of 90?
4. Why is the exponent form useful in prime factorization?
5. What is the prime factorization of a square number, like 49?

#### Tip:
When finding prime factorizations, start by dividing by the smallest prime (2), and proceed with larger primes if necessary.

Find the prime factorization of 45. Write in exponent form.

Learn how to find the prime factorization of 45 in exponent form. This step-by-step guide explains the breakdown of 45 into prime factors and presents the final answer as 3^2 × 5^1, ideal for students in Grades 5-7.

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