To find the prime factorization of 45 in exponent form, we need to break it down into its prime factors.

1. Start by dividing 45 by the smallest prime number, which is 3: $45 \div 3 = 15$

2. Divide 15 by 3 again: $15 \div 3 = 5$

3. Now, 5 is a prime number, so the division stops here.

The prime factors of 45 are $3$ and $5$, with $3$ appearing twice. In exponent form, the prime factorization of 45 is: $45 = 3^2 \times 5^1$

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Related Questions:

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Tip:

When finding prime factorizations, start by dividing by the smallest prime (2), and proceed with larger primes if necessary.