The prime factorization of 6912 is:

$6912 = 2^8 \times 3^3$

Steps:

1. Start dividing by the smallest prime number, 2: $6912 \div 2 = 3456$
2. Divide 3456 by 2: $3456 \div 2 = 1728$
3. Continue dividing by 2: $1728 \div 2 = 864, \quad 864 \div 2 = 432, \quad 432 \div 2 = 216$ $216 \div 2 = 108, \quad 108 \div 2 = 54, \quad 54 \div 2 = 27$
4. Now divide 27 by the next smallest prime number, 3: $27 \div 3 = 9, \quad 9 \div 3 = 3, \quad 3 \div 3 = 1$ Thus, the prime factorization of 6912 is $2^8 \times 3^3$.

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Related Questions:

1. What is the prime factorization of a number close to 6912, like 6913?
2. How can we use the prime factorization to find the number of divisors of 6912?
3. What is the sum of the divisors of 6912 using its prime factorization?
4. How does prime factorization help in simplifying square roots of large numbers?
5. How does the prime factorization help in finding the greatest common divisor (GCD) of 6912 with another number?

Tip: When dealing with large numbers, breaking them down into prime factors helps in understanding their properties like divisibility, common factors, and more.