The question asks for the prime factorization of 128 in index form. To solve this, we will break down 128 into its prime factors.

1. Start with 128 and divide by the smallest prime number, which is 2: $128 \div 2 = 64$
2. Keep dividing by 2: $64 \div 2 = 32$ $32 \div 2 = 16$ $16 \div 2 = 8$ $8 \div 2 = 4$ $4 \div 2 = 2$ $2 \div 2 = 1$

Since we divided by 2 six times, the prime factorization of 128 is: $128 = 2^7$

Would you like a more detailed explanation of the process or further examples of prime factorization?

Here are 5 related questions you might find interesting:

1. How do you find the prime factorization of numbers larger than 128?
2. How do prime factorizations help with simplifying fractions?
3. What is the difference between prime factorization and finding greatest common factors?
4. How can prime factorization be used to find the least common multiple (LCM)?
5. What is the importance of prime numbers in cryptography?

Tip: When finding prime factors, always start with the smallest prime number, which is 2, and continue until the number is fully divided.