Math Problem Statement

Prime factorization of 116 + 138i

Solution

To find the prime factorization of the complex number 116+138i116 + 138i, we'll follow these steps:

Step 1: Determine if 116+138i116 + 138i can be factored into simpler Gaussian integers.

A Gaussian integer is a complex number of the form a+bia + bi where both aa and bb are integers. Prime factorization in the Gaussian integers involves finding Gaussian primes, which are irreducible elements in the ring of Gaussian integers.

Step 2: Calculate the norm of the number.

The norm of a Gaussian integer a+bia + bi is given by: N(a+bi)=a2+b2N(a + bi) = a^2 + b^2 For 116+138i116 + 138i, the norm is: N(116+138i)=1162+1382=13456+19044=32500N(116 + 138i) = 116^2 + 138^2 = 13456 + 19044 = 32500

Step 3: Factor the norm.

The norm N(116+138i)=32500N(116 + 138i) = 32500 can be factored into prime numbers in the usual way: 32500=22×54×1332500 = 2^2 \times 5^4 \times 13

Step 4: Identify potential Gaussian prime factors.

Since the norm is the product of primes, and since each prime norm corresponds to a Gaussian prime, we consider the primes dividing the norm:

  • 22 has norm 2.
  • 55 has norm 5.
  • 1313 has norm 13.

Gaussian primes can also have non-integer norms if they are sums of squares corresponding to prime numbers.

Step 5: Perform trial division by Gaussian primes.

We now attempt to divide 116+138i116 + 138i by Gaussian primes corresponding to 22, 55, and 1313.

  1. Dividing by 1+i1 + i (norm 2): 116+138i1+i=(116+138i)(1i)2=116116i+138i1382=22+22i2=11+11i\frac{116 + 138i}{1 + i} = \frac{(116 + 138i)(1 - i)}{2} = \frac{116 - 116i + 138i - 138}{2} = \frac{-22 + 22i}{2} = -11 + 11i Hence, 116+138i=(1+i)(11+11i)116 + 138i = (1 + i)(-11 + 11i).

  2. Further factorization:

    • Next, consider 11+11i-11 + 11i which has a norm of (11)2+112=242(-11)^2 + 11^2 = 242.

    • The norm 242=2×112242 = 2 \times 11^2.

    • We can factor 11+11i-11 + 11i by recognizing it as 11(1i)-11(1 - i).

Thus, the prime factorization in the Gaussian integers is: 116+138i=(1+i)(1i)×(11)×11=(11)(11)(2)(1+i)(1i)116 + 138i = (1 + i)(1 - i) \times (-11) \times 11 = (-11)(11)(2)(1 + i)(1 - i) The factors (1+i)(1 + i) and (1i)(1 - i) are Gaussian primes with norms of 2.

Final Prime Factorization:

The final prime factorization is: 116+138i=2×11×(11)×(1+i)×(1i)116 + 138i = 2 \times 11 \times (-11) \times (1 + i) \times (1 - i)

This represents the product of Gaussian primes, including negative integers.

Would you like more details on any step or have any further questions?

Related Questions:

  1. What is the prime factorization of a complex number in general?
  2. How can Gaussian primes be characterized?
  3. What is the significance of the norm in Gaussian integers?
  4. What are the rules for dividing complex numbers?
  5. How does the prime factorization of complex numbers differ from integers?
  6. Can you explain more about how to determine if a Gaussian integer is a prime?
  7. How does the Euclidean algorithm apply in the context of Gaussian integers?
  8. What is the importance of Gaussian integers in number theory?

Tip:

When dealing with complex numbers, always consider the norms to guide the factorization process.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Gaussian Integers
Prime Factorization

Formulas

Norm of a Gaussian Integer

Theorems

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Suitable Grade Level

Advanced High School