Math Problem Statement

Prestressing procedure. for the concentrically loaded member, compute the deformation and the change in force that occurs in the tendon and the concrete before and after the transfer. the reduction in the initial tendon force due to elastic shortening of the concrete may be neglected. Given: Aps=0.5 in^2. Ac=100 in^2, L0=720 in., Ec=4,400 kips/in^2, Es=25000 kips/in^2, and fsi=180 kips/in^2

Solution

To compute the deformation and the change in force in the tendon and concrete for a concentrically loaded prestressed member, we need to follow these steps:

Given Data:

  • Area of prestressing steel (Aps): 0.5in20.5 \, \text{in}^2
  • Area of concrete section (Ac): 100in2100 \, \text{in}^2
  • Initial length of the member (L0): 720in720 \, \text{in}
  • Modulus of elasticity of concrete (Ec): 4400kips/in24400 \, \text{kips/in}^2
  • Modulus of elasticity of steel (Es): 25000kips/in225000 \, \text{kips/in}^2
  • Initial stress in the tendon (fsi): 180kips/in2180 \, \text{kips/in}^2

Step 1: Calculate the Initial Prestressing Force in the Tendon

The initial force in the tendon before transfer can be computed using: Psi=fsi×ApsP_{si} = f_{si} \times A_{ps} Psi=180kips/in2×0.5in2=90kipsP_{si} = 180 \, \text{kips/in}^2 \times 0.5 \, \text{in}^2 = 90 \, \text{kips}

Step 2: Compute the Deformation in Concrete

The deformation (shortening) in the concrete can be calculated using: ΔLc=Psi×L0Ac×Ec\Delta L_c = \frac{P_{si} \times L_0}{A_c \times E_c} ΔLc=90kips×720in100in2×4400kips/in2\Delta L_c = \frac{90 \, \text{kips} \times 720 \, \text{in}}{100 \, \text{in}^2 \times 4400 \, \text{kips/in}^2} ΔLc=64800kipsin440000kips=0.1473in\Delta L_c = \frac{64800 \, \text{kips} \cdot \text{in}}{440000 \, \text{kips}} = 0.1473 \, \text{in}

Step 3: Compute the Deformation in the Tendon

Since the tendon and the concrete are bonded, the deformation in the tendon will be the same as the deformation in the concrete: ΔLs=ΔLc=0.1473in\Delta L_s = \Delta L_c = 0.1473 \, \text{in}

Step 4: Calculate the Change in Force in the Tendon

The change in force in the tendon due to this deformation can be calculated using Hooke's Law: ΔPs=ΔLs×Es×ApsL0\Delta P_s = \frac{\Delta L_s \times E_s \times A_{ps}}{L_0} ΔPs=0.1473in×25000kips/in2×0.5in2720in\Delta P_s = \frac{0.1473 \, \text{in} \times 25000 \, \text{kips/in}^2 \times 0.5 \, \text{in}^2}{720 \, \text{in}} ΔPs=1841.25kipsin720in=2.56kips\Delta P_s = \frac{1841.25 \, \text{kips} \cdot \text{in}}{720 \, \text{in}} = 2.56 \, \text{kips}

Step 5: Calculate the Final Force in the Tendon After Transfer

The final force in the tendon after transfer is: Psf=PsiΔPsP_{sf} = P_{si} - \Delta P_s Psf=90kips2.56kips=87.44kipsP_{sf} = 90 \, \text{kips} - 2.56 \, \text{kips} = 87.44 \, \text{kips}

Summary of Results:

  • Deformation in concrete and tendon: ΔLc=ΔLs=0.1473in\Delta L_c = \Delta L_s = 0.1473 \, \text{in}
  • Change in force in tendon: ΔPs=2.56kips\Delta P_s = 2.56 \, \text{kips}
  • Final force in tendon after transfer: Psf=87.44kipsP_{sf} = 87.44 \, \text{kips}

Questions:

  1. What is the significance of the change in force in the tendon after the transfer?
  2. How would the deformation change if the modulus of elasticity of the concrete was higher?
  3. How does the area of the prestressing steel affect the final force in the tendon?
  4. What would be the impact on the results if elastic shortening was considered?
  5. Can the same method be applied if the load was eccentric?

Tip:

Ensure that when performing these calculations, the units are consistently maintained throughout to avoid errors in the final results.

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Math Problem Analysis

Mathematical Concepts

Prestressed Concrete
Elastic Deformation
Hooke's Law

Formulas

Initial Prestressing Force: P_si = f_si × A_ps
Deformation in Concrete: ΔL_c = (P_si × L_0) / (A_c × E_c)
Deformation in Tendon: ΔL_s = ΔL_c
Change in Force in Tendon: ΔP_s = (ΔL_s × E_s × A_ps) / L_0
Final Force in Tendon: P_sf = P_si - ΔP_s

Theorems

Hooke's Law

Suitable Grade Level

College Level