Use the equation to predict the life expectancy of males in 

20082008.

To predict the life expectancy of males in 2008 using the equation \( E = 0.4t + 64.3 \), we first need to determine the value of \( t \) for the year 2008. Since \( t \) represents the number of years since 1995, we calculate \( t \) as follows:

\[
t = 2008 - 1995 = 13
\]

Next, we substitute \( t = 13 \) into the equation:

\[
E = 0.4 \cdot 13 + 64.3
\]

Now, calculate the value:

\[
E = 0.4 \times 13 + 64.3 = 5.2 + 64.3 = 69.5
\]

So, the predicted life expectancy of males in 2008 is 69.5 years.

Would you like more details or have any questions?

Here are 5 additional questions you might want to ask:

1. How can we verify the accuracy of our prediction?
2. How do we handle predictions for years outside the range of our data points?
3. What are the limitations of using a linear model for predicting life expectancy?
4. Can we use other types of models for more accurate predictions? If so, which ones?
5. How do changes in variables like healthcare, lifestyle, and environment affect life expectancy predictions?

**Tip:** Always check the reasonableness of your predictions by considering external factors and comparing them to historical trends.

Learn how to predict the life expectancy of males in 2008 using a linear equation. This problem involves calculating using the formula E = 0.4t + 64.3, where t represents the number of years since 1995. Suitable for students in Grades 9-12 interested in linear equations and applications in real-world data analysis.

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