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The problem states that the image point of \( A \) after a translation left 3 units and down 3 units is the point \( B(-8, -3) \). We need to determine the coordinates of the pre-image point \( A \).

To reverse a translation:
- A translation left by 3 units means to go right by 3 units.
- A translation down by 3 units means to go up by 3 units.

Given point \( B(-8, -3) \), to find \( A \):
- Reverse the horizontal shift: Add 3 to the x-coordinate of \( B \).
\[ -8 + 3 = -5 \]
- Reverse the vertical shift: Add 3 to the y-coordinate of \( B \).
\[ -3 + 3 = 0 \]

Thus, the coordinates of the pre-image point \( A \) are:
\[ A(-5, 0) \]

Would you like more details, or do you have any other questions?

Here are 5 related questions for further exploration:
1. What happens if the translation had been up instead of down?
2. How do you determine the new coordinates after a different type of transformation (e.g., reflection)?
3. How can translations be represented algebraically?
4. What is the geometric interpretation of translating a shape or point?
5. What happens if you translate a point in both directions (left-right and up-down)?

**Tip**: When reversing translations, always think of "undoing" the steps applied, such as moving in the opposite direction.

The image point of A after a translation left 3 units and down 3 units is the point B(-8, -3). Determine the coordinates of the pre-image point A.

Learn how to determine the pre-image point A given the translated point B(-8, -3) after a translation left by 3 units and down by 3 units. This problem involves key concepts in translation and coordinate geometry, suitable for students in Grades 6-8.

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