Math Problem Statement

Find the interval of convergence for the power series ∑ a_n (x - 2)^{2n}, given that lim_{n→∞} |a_n / a_{n+1}| = 4.

Solution

The problem asks to find the interval of convergence for the power series:

n=0an(x2)2n\sum_{n=0}^{\infty} a_n (x - 2)^{2n} with the condition: limnanan+1=4.\lim_{n \to \infty} \left| \frac{a_n}{a_{n+1}} \right| = 4.

Solution Outline:

  1. Apply the Ratio Test for Convergence: To find the radius of convergence RR, we can apply the ratio test to the general term of the power series. The series has the form: n=0an(x2)2n.\sum_{n=0}^{\infty} a_n (x - 2)^{2n}. For the ratio test, we analyze the general term Tn=an(x2)2nT_n = a_n (x - 2)^{2n} by computing: limnTn+1Tn.\lim_{n \to \infty} \left| \frac{T_{n+1}}{T_n} \right|. This simplifies to: limnan+1(x2)2(n+1)an(x2)2n=limnan+1an(x2)2.\lim_{n \to \infty} \left| \frac{a_{n+1} (x - 2)^{2(n+1)}}{a_n (x - 2)^{2n}} \right| = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \cdot |(x - 2)^2|.

  2. Use the given limit: It is provided that: limnanan+1=4.\lim_{n \to \infty} \left| \frac{a_n}{a_{n+1}} \right| = 4. This means: limnan+1an=14.\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \frac{1}{4}.

  3. Set up the condition for convergence: The ratio test tells us that the series converges if: limnTn+1Tn<1.\lim_{n \to \infty} \left| \frac{T_{n+1}}{T_n} \right| < 1. Substituting in the known values: 14(x2)2<1.\frac{1}{4} \cdot |(x - 2)^2| < 1. Simplifying: (x2)2<4.|(x - 2)^2| < 4. Taking the square root: x2<2.|x - 2| < 2.

  4. Interval of convergence: The inequality x2<2|x - 2| < 2 gives the radius of convergence R=2R = 2. Therefore, the interval of convergence is: 0<x<4.0 < x < 4.

However, to find the exact interval of convergence, we need to check the behavior of the series at the endpoints x=0x = 0 and x=4x = 4. These boundary cases can be examined by substituting the values into the series and checking if they converge.

Would you like a detailed check of the boundary points or any other clarifications?

Here are 5 related questions you might find helpful:

  1. How is the ratio test applied in general for power series?
  2. What are some methods to check convergence at the boundary points of a series?
  3. Can the radius of convergence differ from the interval of convergence?
  4. How does changing the general term affect the convergence of a power series?
  5. What is the significance of the convergence criteria xc<R|x - c| < R for power series?

Tip: Always check the boundary points separately when determining the interval of convergence.

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Math Problem Analysis

Mathematical Concepts

Power series
Interval of convergence
Ratio test

Formulas

lim_{n→∞} |a_n / a_{n+1}| = L (Ratio Test)
Radius of Convergence: |x - c| < R
Interval of Convergence: c - R < x < c + R

Theorems

Ratio Test

Suitable Grade Level

Undergraduate or advanced high school level (Grades 11-12)