Math Problem Statement

In 2010, the population of a city was 231,000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 3%. To the nearest 100 people, what was the population in 2020?

Solution

To find the population of the city in 2020, we calculate the growth and decline in two stages:

Step 1: Population growth from 2010 to 2015

The population in 2010 was 231,000, and it grew by 5% from 2010 to 2015.
To calculate the population in 2015: Population in 2015=231,000×(1+0.05)=231,000×1.05=242,550\text{Population in 2015} = 231,000 \times (1 + 0.05) = 231,000 \times 1.05 = 242,550

Step 2: Population decline from 2015 to 2020

The population in 2015 was 242,550, and it fell by 3% from 2015 to 2020.
To calculate the population in 2020: Population in 2020=242,550×(10.03)=242,550×0.97=235,273.5\text{Population in 2020} = 242,550 \times (1 - 0.03) = 242,550 \times 0.97 = 235,273.5

Step 3: Round to the nearest 100

The population in 2020, rounded to the nearest 100, is: 235,300\boxed{235,300}

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Related Questions:

  1. What would the population have been in 2020 if the growth from 2010 to 2015 had been 10% instead of 5%?
  2. What is the percentage change in population from 2010 to 2020?
  3. If the population continued to decrease by 3% every 5 years after 2020, what would it be in 2030?
  4. How long would it take for the population to halve, assuming a constant 3% decline every 5 years?
  5. What would the population in 2020 have been if it experienced no changes from 2010?

Tip:

When calculating successive percentage changes, always apply the percentages step-by-step to avoid errors in calculations.

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Math Problem Analysis

Mathematical Concepts

Percentage Growth and Decline
Compound Percentage Calculations
Rounding to the Nearest 100

Formulas

Final Value after Growth = Initial Value × (1 + Growth Rate)
Final Value after Decline = Initial Value × (1 - Decline Rate)
Rounding: Round(x, nearest 100)

Theorems

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Suitable Grade Level

Grades 6-8