Math Problem Statement
In 2010, the population of a city was 231,000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 3%. To the nearest 100 people, what was the population in 2020?
Solution
To find the population of the city in 2020, we calculate the growth and decline in two stages:
Step 1: Population growth from 2010 to 2015
The population in 2010 was 231,000, and it grew by 5% from 2010 to 2015.
To calculate the population in 2015:
Step 2: Population decline from 2015 to 2020
The population in 2015 was 242,550, and it fell by 3% from 2015 to 2020.
To calculate the population in 2020:
Step 3: Round to the nearest 100
The population in 2020, rounded to the nearest 100, is:
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Related Questions:
- What would the population have been in 2020 if the growth from 2010 to 2015 had been 10% instead of 5%?
- What is the percentage change in population from 2010 to 2020?
- If the population continued to decrease by 3% every 5 years after 2020, what would it be in 2030?
- How long would it take for the population to halve, assuming a constant 3% decline every 5 years?
- What would the population in 2020 have been if it experienced no changes from 2010?
Tip:
When calculating successive percentage changes, always apply the percentages step-by-step to avoid errors in calculations.
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Math Problem Analysis
Mathematical Concepts
Percentage Growth and Decline
Compound Percentage Calculations
Rounding to the Nearest 100
Formulas
Final Value after Growth = Initial Value × (1 + Growth Rate)
Final Value after Decline = Initial Value × (1 - Decline Rate)
Rounding: Round(x, nearest 100)
Theorems
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Suitable Grade Level
Grades 6-8
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