Math Problem Statement

Write the equation of the polynomial function of least degree possible with the zeros −1, 1, 3; and passing through the point (2, 7).

Solution

To determine the polynomial function of the least degree with given zeros x=1x = -1, x=1x = 1, and x=3x = 3, and that passes through the point (2,7)(2, 7), we follow these steps:


Step 1: Write the general form of the polynomial function.

The roots x=1x = -1, x=1x = 1, and x=3x = 3 tell us that the polynomial will have the factors:

P(x)=a(x+1)(x1)(x3)P(x) = a(x + 1)(x - 1)(x - 3)

where aa is a constant that we need to determine.


Step 2: Simplify the polynomial.

First, expand the product (x+1)(x1)(x + 1)(x - 1):

(x+1)(x1)=x21(x + 1)(x - 1) = x^2 - 1

Now multiply by the remaining factor (x3)(x - 3):

(x21)(x3)=x33x2x+3(x^2 - 1)(x - 3) = x^3 - 3x^2 - x + 3

Thus, the polynomial in terms of aa is:

P(x)=a(x33x2x+3)P(x) = a \left( x^3 - 3x^2 - x + 3 \right)


Step 3: Use the point (2,7)(2, 7) to find the value of aa.

We are given that the polynomial passes through the point (2,7)(2, 7), meaning when x=2x = 2, P(x)=7P(x) = 7. Substitute x=2x = 2 and P(x)=7P(x) = 7 into the equation:

7=a(233(22)2+3)7 = a \left( 2^3 - 3(2^2) - 2 + 3 \right)

Simplify the expression inside the parentheses:

23=8,3(22)=122^3 = 8, \quad 3(2^2) = 12 8122+3=38 - 12 - 2 + 3 = -3

Thus:

7=a(3)7 = a(-3)

Solve for aa:

a=73=73a = \frac{7}{-3} = -\frac{7}{3}


Step 4: Write the final polynomial function.

Now that we know a=73a = -\frac{7}{3}, the polynomial function is:

P(x)=73(x33x2x+3)P(x) = -\frac{7}{3} \left( x^3 - 3x^2 - x + 3 \right)


Step 5: Expand if needed (optional).

You can leave it in the factored form above, or distribute 73-\frac{7}{3} if necessary:

P(x)=73x3+7x2+73x7P(x) = -\frac{7}{3}x^3 + 7x^2 + \frac{7}{3}x - 7


Would you like further clarifications or any other details?


5 Follow-up Questions:

  1. How do you determine the degree of a polynomial given its zeros?
  2. What would the polynomial look like if it passed through a different point, such as (0,5)(0, 5)?
  3. What is the impact of changing the sign of the coefficient aa in a polynomial function?
  4. How do multiplicities of roots affect the shape of the graph?
  5. Can a polynomial function have non-real roots? How would that change the factorization?

Tip: Always double-check whether the polynomial is of the least degree by confirming that all provided roots are accounted for, without extra factors.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials
Roots of Polynomials

Formulas

General form of a polynomial P(x) = a(x + 1)(x - 1)(x - 3)
Simplification: P(x) = a(x^3 - 3x^2 - x + 3)
Point substitution to find constant a: 7 = a(-3)

Theorems

Factor Theorem
Zero Product Property

Suitable Grade Level

Grades 10-12