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The given problem asks for a polynomial with the specified zeros \( i \), \( \sqrt{2} \), and \( -i \).

### Step-by-step approach:

1. **Zerors Identification**: The polynomial has the zeros \( i \), \( \sqrt{2} \), and \( -i \). Since \( i \) and \( -i \) are complex conjugates, their product will form a quadratic factor. The zero \( \sqrt{2} \) contributes another factor.

2. **Form the Factors**:
   - The factors corresponding to the zeros are:
     \[
     (x - i)(x + i) = x^2 + 1 \quad \text{(product of conjugates)}
     \]
     \[
     (x - \sqrt{2}) \quad \text{(real root)}
     \]

3. **Construct the Polynomial**: 
   - Now multiply these factors:
     \[
     (x^2 + 1)(x - \sqrt{2}) = x^3 - \sqrt{2}x^2 + x - \sqrt{2}
     \]

Thus, the polynomial is:
\[
x^3 - \sqrt{2}x^2 + x - \sqrt{2}
\]

### Correct Answer: 
This matches option **C** in the list.

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Would you like further clarification on this? 

Here are 5 related questions for deeper understanding:

1. How do you identify factors from given zeros?
2. Why do complex conjugates always produce quadratic factors?
3. What happens when you multiply binomials with irrational or complex terms?
4. Can there be more than one correct polynomial for a given set of zeros?
5. How do you confirm if a certain form of a polynomial satisfies the given zeros?

**Tip**: When working with zeros involving complex or irrational numbers, always check if conjugates are included to ensure the polynomial has real coefficients.

Find a polynomial with the given zeros: i, sqrt(2), -i

This page explains how to find a polynomial with the given zeros i, sqrt(2), and -i. It involves using the concepts of complex conjugates and factoring polynomials. Suitable for students in Grades 10-12.

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