Math Problem Statement

For each list of the polynomials in P≤3(R), determine whether the first polynomial can be expressed as a linear combination of the other two: a) x 3 + 3x 2 − 1, x 3 − 3x + 5, x 3 + 2x 2 − x + 1

Solution

We are tasked with determining if the first polynomial can be expressed as a linear combination of the other two. For the given polynomials in P3(R)P_{\leq 3}(\mathbb{R}), the question is to check if the first polynomial p1(x)=x3+3x21p_1(x) = x^3 + 3x^2 - 1 can be expressed as a linear combination of the second polynomial p2(x)=x33x+5p_2(x) = x^3 - 3x + 5 and the third polynomial p3(x)=x3+2x2x+1p_3(x) = x^3 + 2x^2 - x + 1.

This can be done by checking if there exist scalars aa and bb such that:

p1(x)=ap2(x)+bp3(x)p_1(x) = a \cdot p_2(x) + b \cdot p_3(x)

Substitute the given polynomials into this expression:

x3+3x21=a(x33x+5)+b(x3+2x2x+1)x^3 + 3x^2 - 1 = a(x^3 - 3x + 5) + b(x^3 + 2x^2 - x + 1)

Now, expand the right-hand side:

a(x33x+5)=ax33ax+5aa(x^3 - 3x + 5) = a \cdot x^3 - 3a \cdot x + 5a b(x3+2x2x+1)=bx3+2bx2bx+bb(x^3 + 2x^2 - x + 1) = b \cdot x^3 + 2b \cdot x^2 - b \cdot x + b

Combining the two expansions, we get:

ax33ax+5a+bx3+2bx2bx+b=(a+b)x3+2bx2+(3ab)x+(5a+b)a \cdot x^3 - 3a \cdot x + 5a + b \cdot x^3 + 2b \cdot x^2 - b \cdot x + b = (a + b) \cdot x^3 + 2b \cdot x^2 + (-3a - b) \cdot x + (5a + b)

Now, equate the coefficients of the powers of xx from both sides:

  1. Coefficient of x3x^3: a+b=1a + b = 1
  2. Coefficient of x2x^2: 2b=32b = 3 From this, we get b=32b = \frac{3}{2}.
  3. Coefficient of xx: 3ab=0-3a - b = 0 Substituting b=32b = \frac{3}{2}, we get: 3a32=0a=12-3a - \frac{3}{2} = 0 \quad \Rightarrow \quad a = -\frac{1}{2}
  4. Constant term: 5a+b=15a + b = -1 Substituting a=12a = -\frac{1}{2} and b=32b = \frac{3}{2}, we get: 5(12)+32=52+32=15\left(-\frac{1}{2}\right) + \frac{3}{2} = -\frac{5}{2} + \frac{3}{2} = -1 This is true.

Since all the equations are satisfied, the first polynomial p1(x)=x3+3x21p_1(x) = x^3 + 3x^2 - 1 can be expressed as a linear combination of the other two polynomials.

The linear combination is:

p1(x)=12p2(x)+32p3(x)p_1(x) = -\frac{1}{2} \cdot p_2(x) + \frac{3}{2} \cdot p_3(x)


Would you like further details or have any questions?

Here are 5 related questions you might find helpful:

  1. Can any polynomial in P3(R)P_{\leq 3}(\mathbb{R}) always be expressed as a linear combination of others in the same space?
  2. What does it mean for polynomials to be linearly dependent in a vector space?
  3. How can the concept of basis polynomials be applied to higher-degree polynomials?
  4. How would the solution change if we had an extra polynomial to consider?
  5. What is the geometric interpretation of expressing one polynomial as a linear combination of others?

Tip: To solve systems of equations like this efficiently, matrix methods such as Gaussian elimination can be used.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Polynomials
Linear Combinations

Formulas

p1(x) = a * p2(x) + b * p3(x)
Equating coefficients of powers of x

Theorems

Linear Independence and Dependence of Polynomials

Suitable Grade Level

Undergraduate (University Level)