Math Problem Statement

The polynomials 1 + x, 1 + x^2, 1 − x + x^2, x + x^3 form a basis for all cubic polynomials. Find the coordinate of 1 + x with respect to the basis from the previous problem.

Solution

Let's break down the problem step by step.

Part 1:

You are given a basis for the vector space of all cubic polynomials: {1+x,1+x2,1x+x2,x+x3}\{1 + x, 1 + x^2, 1 - x + x^2, x + x^3\}

This means that any cubic polynomial can be written as a linear combination of these four polynomials.

Part 2:

You are asked to find the coordinate of 1+x1 + x with respect to this basis. That is, you need to express 1+x1 + x as a linear combination of the given basis vectors: 1+x=c1(1+x)+c2(1+x2)+c3(1x+x2)+c4(x+x3)1 + x = c_1(1 + x) + c_2(1 + x^2) + c_3(1 - x + x^2) + c_4(x + x^3) Where c1,c2,c3,c4c_1, c_2, c_3, c_4 are scalars (coordinates) to be determined.

Step-by-Step Process:

  1. Express the equation: We already have the polynomial on the left-hand side, 1+x1 + x. Now, we expand the right-hand side: c1(1+x)+c2(1+x2)+c3(1x+x2)+c4(x+x3)c_1(1 + x) + c_2(1 + x^2) + c_3(1 - x + x^2) + c_4(x + x^3) Expanding each term: c1(1+x)=c1+c1xc_1(1 + x) = c_1 + c_1x c2(1+x2)=c2+c2x2c_2(1 + x^2) = c_2 + c_2x^2 c3(1x+x2)=c3c3x+c3x2c_3(1 - x + x^2) = c_3 - c_3x + c_3x^2 c4(x+x3)=c4x+c4x3c_4(x + x^3) = c_4x + c_4x^3

    Adding these together: (c1+c2+c3)+(c1c3+c4)x+(c2+c3)x2+c4x3(c_1 + c_2 + c_3) + (c_1 - c_3 + c_4)x + (c_2 + c_3)x^2 + c_4x^3

  2. Match the coefficients: Now, match the coefficients of 11, xx, x2x^2, and x3x^3 from both sides:

    • Constant term: 1=c1+c2+c31 = c_1 + c_2 + c_3
    • Coefficient of xx: 1=c1c3+c41 = c_1 - c_3 + c_4
    • Coefficient of x2x^2: 0=c2+c30 = c_2 + c_3
    • Coefficient of x3x^3: 0=c40 = c_4
  3. Solve the system: From the equation c4=0c_4 = 0, we substitute into the other equations:

    • 0=c40 = c_4, so the equation for x3x^3 is already satisfied.
    • From c2+c3=0c_2 + c_3 = 0, we get c3=c2c_3 = -c_2.
    • Substituting c3=c2c_3 = -c_2 into the equation c1c3+c4=1c_1 - c_3 + c_4 = 1, we get: c1+c2=1c_1 + c_2 = 1
    • Now substitute c3=c2c_3 = -c_2 into c1+c2+c3=1c_1 + c_2 + c_3 = 1, which simplifies to: c1=1c_1 = 1
  4. Find the remaining coefficients:

    • We now know c1=1c_1 = 1. Substituting this into c1+c2=1c_1 + c_2 = 1, we find c2=0c_2 = 0.
    • Since c3=c2c_3 = -c_2, we get c3=0c_3 = 0.
    • Finally, we already know c4=0c_4 = 0.

Conclusion:

The coordinates of 1+x1 + x with respect to the given basis are: [1+x]=(1,0,0,0)[1 + x] = (1, 0, 0, 0)

Would you like further details on any of these steps?

Five Related Questions:

  1. What does it mean for a set of polynomials to form a basis for a vector space?
  2. How would you find the coordinate vector of a higher-degree polynomial with respect to a basis?
  3. Can you always express any polynomial as a linear combination of basis polynomials?
  4. What is the dimension of the vector space of cubic polynomials?
  5. How does the concept of polynomial vector spaces extend to multivariable polynomials?

Tip:

When finding coordinates with respect to a basis, ensure the system of equations you form from comparing coefficients is consistent and reflects each power of xx.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Polynomial Basis
Vector Spaces

Formulas

Linear combination of basis vectors

Theorems

Basis of a Vector Space
Coordinate Vectors

Suitable Grade Level

Undergraduate level (Linear Algebra)