Math Problem Statement

Describe the end behaviors of the graph of the function: f(x) = -3x^5 + 2x^3 - 7x + 2, and evaluate the function f(x) = -2x^3 - 3x^2 + x at x = 2.

Solution

Let's address both parts of the image you uploaded:

1. End Behavior of the Function:

The function given is f(x)=3x5+2x37x+2f(x) = -3x^5 + 2x^3 - 7x + 2. To determine the end behavior, we focus on the term with the highest degree (the leading term), which is 3x5-3x^5.

  • As x+x \to +\infty, the term 3x5-3x^5 dominates and becomes very negative, so f(x)f(x) \to -\infty.
  • As xx \to -\infty, the term 3x5-3x^5 also becomes negative because (x)5=x5(-x)^5 = -x^5, so f(x)+f(x) \to +\infty.

Thus, the end behavior is:

  • f(x)f(x) \to -\infty as x+x \to +\infty
  • f(x)+f(x) \to +\infty as xx \to -\infty

This corresponds to the second option in the list.

2. Evaluating the Function:

The second problem asks to evaluate the function f(x)=2x33x2+xf(x) = -2x^3 - 3x^2 + x at x=2x = 2.

Substitute x=2x = 2 into the function: f(2)=2(2)33(2)2+2f(2) = -2(2)^3 - 3(2)^2 + 2 f(2)=2(8)3(4)+2f(2) = -2(8) - 3(4) + 2 f(2)=1612+2f(2) = -16 - 12 + 2 f(2)=26f(2) = -26

So, the value of the function at x=2x = 2 is 26-26.

Summary:

  1. The correct end behavior is: f(x)+f(x) \to +\infty as xx \to -\infty, and f(x)f(x) \to -\infty as x+x \to +\infty.
  2. The value of the function at x=2x = 2 is 26-26.

Would you like more details on any of these steps or additional questions? Here are some related questions for practice:

  1. What would the end behavior be for f(x)=3x4+x25f(x) = 3x^4 + x^2 - 5?
  2. How does the degree and leading coefficient of a polynomial affect its end behavior?
  3. If f(x)=x6+4x3xf(x) = -x^6 + 4x^3 - x, what are the end behaviors as xx \to \infty and xx \to -\infty?
  4. Evaluate f(x)=x34x2+7x5f(x) = x^3 - 4x^2 + 7x - 5 at x=1x = -1.
  5. How do higher-degree terms in a polynomial influence its graph's shape?

Tip:

When determining the end behavior of a polynomial, always focus on the leading term (the term with the highest degree) because it dominates as xx grows large in either direction.

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Math Problem Analysis

Mathematical Concepts

End Behavior of Polynomials
Polynomial Function Evaluation

Formulas

End behavior depends on the leading term of the polynomial
Substitution for evaluating functions

Theorems

End Behavior Theorem for Polynomials
Evaluation of Polynomials

Suitable Grade Level

Grades 10-12