Math Problem Statement

Write z1 and z2 in polar form. z1 = −12, z2 =

3

  • i z1 =

z2

Check your radius and your angle. Find the product z1z2 and the quotients z1 z2 and 1 z1 . Express your answers in polar form. z1z2

z1 z2

1 z1

Solution

To express z1z_1 and z2z_2 in polar form, let's start by identifying the radius rr and the angle θ\theta for each.

1. Writing z1z_1 and z2z_2 in Polar Form

For z1=12z_1 = -12:

  • Radius r1r_1: r1=z1=12=12r_1 = |z_1| = |-12| = 12
  • Angle θ1\theta_1: Since z1z_1 is on the negative real axis, θ1=π\theta_1 = \pi radians (or 180°).

Therefore: z1=12cis(π)where cis(θ)=cos(θ)+isin(θ)z_1 = 12 \text{cis}(\pi) \quad \text{where } \text{cis}(\theta) = \cos(\theta) + i\sin(\theta)

For z2=3+iz_2 = 3 + i:

  • Radius r2r_2: r2=z2=32+12=9+1=10r_2 = |z_2| = \sqrt{3^2 + 1^2} = \sqrt{9 + 1} = \sqrt{10}
  • Angle θ2\theta_2: θ2=tan1(13)\theta_2 = \tan^{-1}\left(\frac{1}{3}\right) This angle is in the first quadrant.

Thus: z2=10cis(tan1(1/3))z_2 = \sqrt{10} \text{cis}(\tan^{-1}(1/3))

2. Finding the Product z1z2z_1z_2

The product in polar form can be calculated using: z1z2=r1r2cis(θ1+θ2)z_1 z_2 = r_1 r_2 \text{cis}(\theta_1 + \theta_2)

  • r1r2r_1 r_2: r1r2=1210r_1 r_2 = 12 \cdot \sqrt{10}
  • θ1+θ2\theta_1 + \theta_2: θ1+θ2=π+tan1(1/3)\theta_1 + \theta_2 = \pi + \tan^{-1}(1/3)

Therefore: z1z2=1210cis(π+tan1(1/3))z_1 z_2 = 12\sqrt{10} \text{cis}\left(\pi + \tan^{-1}(1/3)\right)

3. Finding the Quotient z1z2\frac{z_1}{z_2}

The quotient in polar form is calculated using: z1z2=r1r2cis(θ1θ2)\frac{z_1}{z_2} = \frac{r_1}{r_2} \text{cis}(\theta_1 - \theta_2)

  • r1r2\frac{r_1}{r_2}: r1r2=1210\frac{r_1}{r_2} = \frac{12}{\sqrt{10}}
  • θ1θ2\theta_1 - \theta_2: θ1θ2=πtan1(1/3)\theta_1 - \theta_2 = \pi - \tan^{-1}(1/3)

Thus: z1z2=1210cis(πtan1(1/3))\frac{z_1}{z_2} = \frac{12}{\sqrt{10}} \text{cis}\left(\pi - \tan^{-1}(1/3)\right)

4. Finding 1z1\frac{1}{z_1}

We can find the reciprocal of z1z_1 as: 1z1=1r1cis(θ1)\frac{1}{z_1} = \frac{1}{r_1} \text{cis}(-\theta_1)

  • 1r1\frac{1}{r_1}: 1r1=112\frac{1}{r_1} = \frac{1}{12}
  • θ1-\theta_1: θ1=π-\theta_1 = -\pi

Therefore: 1z1=112cis(π)\frac{1}{z_1} = \frac{1}{12} \text{cis}(-\pi)

Final Results:

z1=12cis(π)z_1 = 12 \text{cis}(\pi) z2=10cis(tan1(1/3))z_2 = \sqrt{10} \text{cis}(\tan^{-1}(1/3)) z1z2=1210cis(π+tan1(1/3))z_1 z_2 = 12\sqrt{10} \text{cis}\left(\pi + \tan^{-1}(1/3)\right) z1z2=1210cis(πtan1(1/3))\frac{z_1}{z_2} = \frac{12}{\sqrt{10}} \text{cis}\left(\pi - \tan^{-1}(1/3)\right) 1z1=112cis(π)\frac{1}{z_1} = \frac{1}{12} \text{cis}(-\pi)

Would you like more details on any part of this solution or have any questions?

Related Questions:

  1. How can we convert angles from radians to degrees?
  2. What is the significance of the polar form in complex number calculations?
  3. How do you determine the argument θ\theta for complex numbers in different quadrants?
  4. Why is the product of two complex numbers simply the product of their magnitudes and the sum of their angles?
  5. What are some real-world applications of complex numbers in polar form?

Tip:

When calculating the argument θ\theta for a complex number, always check the quadrant to avoid incorrect angle measurements.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Coordinates
Multiplication and Division of Complex Numbers

Formulas

Polar form of a complex number: z = r(cosθ + isinθ)
Multiplication of complex numbers in polar form: z1 * z2 = r1 * r2 cis(θ1 + θ2)
Division of complex numbers in polar form: z1/z2 = (r1/r2) cis(θ1 - θ2)
Reciprocal of a complex number: 1/z = (1/r) cis(-θ)

Theorems

Euler's Formula
De Moivre's Theorem

Suitable Grade Level

Grades 10-12