Math Problem Statement
Review the response and rate each piece. Only mark steps incorrect if they contain a mathematical error. The model may add preamble or summary steps which seem superfluous, but do not mark them incorrect unless they contain a math error.
Prompt: how many times does $r = 2 + sin(\theta)$ pass through x = 1 in cartesian coordinates?
Step 1
To gain insight into this problem, we can plot the function $f(\theta) = 2\cos(\theta) + \frac{1}{2}\sin(2\theta) - 1$ and observe how many times it crosses the $\theta$-axis, which corresponds to the instances where $x = 1$.
Step 2
Alternatively, we can analyze the problem geometrically by plotting the polar equation $r = 2 + \sin(\theta)$ and observing how many times it intersects the vertical line $x = 1$.
Step 3
By plotting the polar equation, we can see that it forms a cardioid shape with the cusp pointing to the right. The line $x = 1$ intersects this cardioid shape twice.
Step 4
Therefore, based on the geometric analysis, the polar equation $r = 2 + \sin(\theta)$ passes through $x = 1$ twice.
Which step is wrong in getting the answer
Solution
Let’s review each step for mathematical correctness:
Step 1
- Incorrect. The expression provided, $f(\theta) = 2\cos(\theta) + \frac{1}{2}\sin(2\theta) - 1$, is not derived correctly. The goal is to find how many times the polar equation $r = 2 + \sin(\theta)$ intersects the vertical line $x = 1$ in Cartesian coordinates. In polar coordinates, $x = r\cos(\theta)$, so we need to set $r\cos(\theta) = 1$. The expression in this step does not reflect that approach, and the form of $f(\theta)$ seems arbitrary and unrelated to solving for $x = 1$.
Step 2
- Correct, but vague. This step suggests an alternative approach to analyze the problem geometrically by plotting the polar equation $r = 2 + \sin(\theta)$ and observing intersections with $x = 1$. While this is conceptually valid, it lacks mathematical rigor or specific details. It would be better to explicitly state that we are looking for where $r\cos(\theta) = 1$.
Step 3
- Correct. This step is accurate. The cardioid formed by $r = 2 + \sin(\theta)$ does indeed intersect the vertical line $x = 1$ twice. Geometrically, this is correct based on the cardioid’s shape and orientation, and the intersections with $x = 1$ can be observed.
Step 4
- Correct. The conclusion is accurate. After correctly analyzing the polar plot, we can conclude that the cardioid passes through $x = 1$ twice.
Summary:
- Step 1 is incorrect due to an erroneous expression for $f(\theta)$.
- Steps 2, 3, and 4 are correct in the geometric approach, though Step 2 could be improved by being more precise.
Rating:
- Step 1: Incorrect
- Step 2: Correct (but could be clearer)
- Step 3: Correct
- Step 4: Correct
Would you like to explore how to solve this problem algebraically or geometrically in more detail?
Here are five related questions:
- How do you convert polar coordinates to Cartesian coordinates?
- How do you derive the equation $r\cos(\theta) = 1$ for this problem?
- Can other types of polar curves intersect the line $x = 1$ more than twice?
- How would the result change if the polar equation were $r = 2 + \cos(\theta)$ instead of $r = 2 + \sin(\theta)$?
- What is the general shape of the polar curve $r = 2 + \sin(\theta)$, and how does it compare to other cardioids?
Tip: In polar coordinates, the relationship between $r$, $\theta$, and $x$ is $x = r\cos(\theta)$. This is useful when analyzing intersections with vertical lines like $x = 1$.
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Math Problem Analysis
Mathematical Concepts
Polar Coordinates
Cartesian Coordinates
Intersection of Curves
Formulas
x = r \cos(\theta)
r = 2 + \sin(\theta)
Theorems
Relationship between polar and cartesian coordinates
Suitable Grade Level
College Level
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