Math Problem Statement

how many times does $r = 2 + sin(\theta)$ pass through x = 1 in cartesian coordinates?

Solution

To determine how many times the polar curve r=2+sin(θ)r = 2 + \sin(\theta) passes through the line x=1x = 1 in Cartesian coordinates, we need to translate the problem into a coordinate system that allows us to compare both equations.

Step 1: Convert Polar to Cartesian Coordinates

In polar coordinates, we know the following relationships between rr and θ\theta, and the Cartesian coordinates xx and yy:

x=rcos(θ)x = r \cos(\theta) y=rsin(θ)y = r \sin(\theta)

Substituting r=2+sin(θ)r = 2 + \sin(\theta) into the equation for xx:

x=(2+sin(θ))cos(θ)x = (2 + \sin(\theta)) \cos(\theta)

We are looking for the values of θ\theta where x=1x = 1, so set the equation equal to 1:

(2+sin(θ))cos(θ)=1(2 + \sin(\theta)) \cos(\theta) = 1

Step 2: Solve the Equation for θ\theta

To solve (2+sin(θ))cos(θ)=1(2 + \sin(\theta)) \cos(\theta) = 1, we can attempt to solve it directly or graphically analyze it to determine how many solutions exist within one period of θ\theta.

Let's proceed graphically or numerically. The equation depends on trigonometric functions, which have periodic behavior, so there might be multiple values of θ\theta within the range [0,2π][0, 2\pi] for which this equation holds.

Step 3: Numerical or Graphical Solution (Discussion)

Without performing a detailed numerical analysis here, it's known that polar

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Cartesian Coordinates
Trigonometric Functions

Formulas

x = r * cos(\theta)
y = r * sin(\theta)
r = 2 + sin(\theta)
(2 + sin(\theta)) * cos(\theta) = 1

Theorems

Trigonometric Identities
Polar-Cartesian Conversion

Suitable Grade Level

Undergraduate Mathematics