Math Problem Statement

A survey of 2302 adults in a certain large country aged 18 and older conducted by a reputable polling organization found that 406 have donated blood in the past two years. Complete parts​ (a) through​ (c) below. Question content area bottom Part 1 ​(a) Obtain a point estimate for the population proportion of adults in the country aged 18 and older who have donated blood in the past two years. ModifyingAbove p with caretequals    0.176 ​(Round to three decimal places as​ needed.) Part 2 ​(b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample can be assumed to be a simple random​ sample, the value of n ModifyingAbove p with caret left parenthesis 1 minus ModifyingAbove p with caret right parenthesis is    enter your response here​, which is greater than or equal to ​10, and the sample size

can be assumed to be less than or equal to​ 5% of the population size. ​(Round to three decimal places as​ needed.)

Solution

Let's tackle the problem step by step.

Part 1: Point Estimate for the Population Proportion

The point estimate for the population proportion pp is calculated using the formula:

p^=xn\hat{p} = \frac{x}{n}

Where:

  • xx = number of adults who donated blood in the past two years (406),
  • nn = total number of adults surveyed (2302).

p^=40623020.176\hat{p} = \frac{406}{2302} \approx 0.176

Thus, the point estimate p^=0.176\hat{p} = 0.176 is already given.


Part 2: Verify the Requirements for Constructing a Confidence Interval

To verify the requirements for constructing a confidence interval, we need to check two key conditions:

  1. The Sample Size Condition: The sample must be large enough. This is typically verified using the expression:

    np^(1p^)10n \hat{p}(1 - \hat{p}) \geq 10

    Let's calculate it:

    • p^=0.176\hat{p} = 0.176,
    • n=2302n = 2302.

    np^(1p^)=2302×0.176×(10.176)n \hat{p}(1 - \hat{p}) = 2302 \times 0.176 \times (1 - 0.176)

    First, calculate 1p^=10.176=0.8241 - \hat{p} = 1 - 0.176 = 0.824.

    Now compute:

    np^(1p^)=2302×0.176×0.824334.24n \hat{p}(1 - \hat{p}) = 2302 \times 0.176 \times 0.824 \approx 334.24

    Since 334.2410334.24 \geq 10, this condition is satisfied.

  2. The Independence Condition: The sample size must be less than or equal to 5% of the population. Since the survey sample includes 2302 people, we need to check that:

    n0.05×population sizen \leq 0.05 \times \text{population size}

    As long as the population is large enough (greater than 46,040 people), this condition is satisfied. In a large country, it is reasonable to assume this holds.


Summary:

  • The point estimate for the population proportion is p^=0.176\hat{p} = 0.176.
  • The conditions for constructing a confidence interval are met because:
    • np^(1p^)=334.2410n \hat{p}(1 - \hat{p}) = 334.24 \geq 10,
    • The sample size of 2302 is likely less than 5% of the population.

Do you have any questions, or would you like further details? Here are some related questions you might explore:

  1. How is the margin of error calculated for this proportion?
  2. What would be the confidence interval for the population proportion with 95% confidence?
  3. How would increasing the sample size affect the confidence interval?
  4. Can the normal approximation be used for any sample size, or are there restrictions?
  5. How does the variability of the proportion affect the required sample size for future surveys?

Tip: The larger the sample size, the narrower the confidence interval, providing a more precise estimate of the population proportion.

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Math Problem Analysis

Mathematical Concepts

Statistics
Population Proportion
Confidence Interval

Formulas

Point Estimate for Population Proportion: p̂ = x/n
Sample Size Condition: n * p̂ * (1 - p̂) ≥ 10
Independence Condition: n ≤ 0.05 * Population Size

Theorems

Central Limit Theorem
Normal Approximation for Proportions

Suitable Grade Level

Grades 10-12