Math Problem Statement

slove this thermo question

A piston-cylinder device with a set of stops initially contains 0.3 kg of steam at 1.0 MPa and 400°C. The location of the stops corresponds to 60 percent of the initial volume. Now the steam is cooled. Determine the compression work if the final state is (a) 1.0 MPa and 250°C and (b) 500 kPa. (c) Also determine the temperature at the final state in part (b).

Solution

This problem involves a piston-cylinder device with a set of stops, initially containing steam, and involves determining the compression work and final temperatures after cooling. Here's the breakdown:

Given dataThis problem involves a piston-cylinder device with a set of stops, initially containing steam, and involves determining the compression work and final temperatures after cooling. Here's the breakdown:

Given

  • Initial state:

    • P1=1.0MPaP_1 = 1.0 \, \text{MPa}
    • T1=400CT_1 = 400^\circ C
    • Mass of steam: m=0.3kgm = 0.3 \, \text{kg}
    • Stops correspond to 60% of the initial volume.
  • Final state:

    • Part (a): P2=1.0MPaP_2 = 1.0 \, \text{MPa}, T2=250CT_2 = 250^\circ C
    • Part (b): P2=500kPaP_2 = 500 \, \text{kPa}

Steps to Solve:

Step 1: Find properties at the initial state

Using steam tables, we find properties of steam at P1=1.0MPaP_1 = 1.0 \, \text{MPa} and T1=400CT_1 = 400^\circ C:

  • From the steam tables, for superheated steam at 1 MPa and 400°C:
    • Specific volume v1v_1
    • Internal energy u1u_1

Now, we can calculate the initial volume: V1=mv1V_1 = m \cdot v_1

Step 2: Determine properties at intermediate state (stops)

The stops limit the volume to 60% of the initial volume: Vstops=0.6V1V_{\text{stops}} = 0.6 \cdot V_1

Step 3: Analyze Part (a) — Final state at P2=1.0MPa,T2=250CP_2 = 1.0 \, \text{MPa}, T_2 = 250^\circ C

At this final state, we use steam tables again for P2=1.0MPaP_2 = 1.0 \, \text{MPa} and T2=250CT_2 = 250^\circ C to find:

  • Specific volume v2v_2
  • Internal energy u2u_2

Next, we compute the work done using: W=P2(VstopsV2)W = P_2 \cdot (V_{\text{stops}} - V_2)

Step 4: Analyze Part (b) — Final state at P2=500kPaP_2 = 500 \, \text{kPa}

Now, at the final state with P2=500kPaP_2 = 500 \, \text{kPa}, we calculate:

  • Use steam tables for specific volume v3v_3 and temperature at this pressure. Since the volume is limited by the stops, we use the volume at stops to compute the final temperature and properties.

Step 5: Calculate Compression Work for Both Cases

The compression work is calculated from: W=PΔVW = P \cdot \Delta V where ΔV\Delta V is the change in volume as the piston moves to the final state.

Let me calculate these details step-by-step next to match the given answers.

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Math Problem Analysis

Mathematical Concepts

Thermodynamics
Work-Energy Principle
Properties of Steam

Formulas

W = P * ΔV
V = m * v
Using Steam Tables for property calculations

Theorems

First Law of Thermodynamics

Suitable Grade Level

Undergraduate Engineering (Thermodynamics)