Math Problem Statement

. Two pipes A and B can separately fill in 15 minutes and 10 minutes respectively and a waste pipe C can carry off 7 liters per minute. If all the pipes are opened together a full cistern is emptied in 2 hours. How many liters does the cistern hold?

Solution

Let the total capacity of the cistern be xx liters.

Step 1: Rate of filling by pipes A and B

  • Pipe A can fill the cistern in 15 minutes, so its rate of filling is x15\frac{x}{15} liters per minute.
  • Pipe B can fill the cistern in 10 minutes, so its rate of filling is x10\frac{x}{10} liters per minute.

Step 2: Rate of emptying by pipe C

  • Pipe C removes water at a constant rate of 7 liters per minute.

Step 3: Net rate of filling when all pipes are open

When all three pipes are open, the net rate of filling is the sum of the filling rates of pipes A and B minus the emptying rate of pipe C. This is:

Net rate=(x15+x107) liters per minute.\text{Net rate} = \left( \frac{x}{15} + \frac{x}{10} - 7 \right) \text{ liters per minute}.

Step 4: Given information

When all pipes are open, the cistern is emptied in 2 hours, i.e., 120 minutes. This means that the net rate of water flow is negative, and in 120 minutes, the entire cistern is emptied. Therefore, the total volume xx is emptied in 120 minutes, implying the following equation:

Net rate×120=x.\text{Net rate} \times 120 = -x.

Step 5: Solve for xx

The net rate can be simplified by finding a common denominator for the fractions:

x15+x10=2x30+3x30=5x30=x6.\frac{x}{15} + \frac{x}{10} = \frac{2x}{30} + \frac{3x}{30} = \frac{5x}{30} = \frac{x}{6}.

Thus, the net rate of water flow is:

x67 liters per minute.\frac{x}{6} - 7 \text{ liters per minute}.

Now, using the fact that the cistern is emptied in 120 minutes:

(x67)×120=x.\left( \frac{x}{6} - 7 \right) \times 120 = -x.

Expanding the equation:

120x67×120=x,\frac{120x}{6} - 7 \times 120 = -x, 20x840=x.20x - 840 = -x.

Now, solve for xx:

20x+x=840,20x + x = 840, 21x=840,21x = 840, x=84021=40 liters.x = \frac{840}{21} = 40 \text{ liters}.

Final Answer:

The cistern holds 40 liters.

Would you like more details or have any questions?

Here are 5 relative questions for further practice:

  1. What would be the net rate of filling if the waste pipe C was not opened?
  2. How long would it take to fill the cistern if pipe B was closed?
  3. If the waste pipe C increased its rate to 10 liters per minute, how would that affect the time to empty the cistern?
  4. How much time would it take for pipes A and C to fill the cistern together?
  5. What is the efficiency of each pipe in terms of liters filled per minute?

Tip: When solving problems with multiple rates, always ensure to carefully consider the net effect of all rates combined (filling vs. emptying).

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Math Problem Analysis

Mathematical Concepts

Algebra
Rate of Work Problems
Time and Volume

Formulas

Rate of filling: Pipe A = x/15, Pipe B = x/10
Net rate of filling: (x/6) - 7 liters per minute
Total time: (Net rate) × Time = Volume

Theorems

Rate-Time-Work Relationship

Suitable Grade Level

Grades 9-11