Math Problem Statement

The piecewise function h(x) is shown on a graph where theres a line from (-4, 3) closed, to (0, 2) closed. and another line with the points (2, 3) open, (4, 5) closed. What is the value of h(2)?

−2 −1 0 3

Solution

The function h(x)h(x) is piecewise, so we need to analyze the value of h(x)h(x) at x=2x = 2 based on the segments provided.

  • The first segment is from (4,3)(-4, 3) to (0,2)(0, 2), with both endpoints closed. This segment is irrelevant since it doesn't include x=2x = 2.

  • The second segment goes from (2,3)(2, 3) to (4,5)(4, 5), with an open circle at (2,3)(2, 3) and a closed circle at (4,5)(4, 5). Since the point at x=2x = 2 is open, this means h(2)h(2) is not defined at 3.

Thus, the function has no defined value at x=2x = 2, and the correct value of h(2)h(2) is:

h(2)=0h(2) = 0

Want more details or have questions about this?

Here are 5 follow-up questions:

  1. What happens to h(x)h(x) if we change the open point at x=2x = 2 to closed?
  2. Can you represent this piecewise function algebraically?
  3. How do open and closed points affect the continuity of a function?
  4. What would h(x)h(x) be at x=4x = 4?
  5. How would the graph change if h(2)h(2) were defined as 3?

Tip: In piecewise functions, always check whether endpoints are open or closed when determining specific values.

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Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Graph Interpretation
Open and Closed Intervals

Formulas

-

Theorems

Continuity and Discontinuity in Piecewise Functions

Suitable Grade Level

Grades 9-11