Math Problem Statement

|x+3|/(x+3) for this piecewise, how do i know which one is inclusive -3 and thenone which is not inclusive

Solution

The expression x+3x+3\frac{|x+3|}{x+3} can be analyzed by determining the behavior of the absolute value function based on the value of x+3x+3. This will help us write the piecewise function and determine where to include or exclude specific points.

1. Behavior of x+3x+3\frac{|x+3|}{x+3}:

  • When x+3>0x + 3 > 0 (i.e., x>3x > -3), x+3=x+3|x + 3| = x + 3. In this case, the expression simplifies as: x+3x+3=x+3x+3=1\frac{|x+3|}{x+3} = \frac{x+3}{x+3} = 1

  • When x+3<0x + 3 < 0 (i.e., x<3x < -3), x+3=(x+3)|x + 3| = -(x + 3). In this case, the expression becomes: x+3x+3=(x+3)x+3=1\frac{|x+3|}{x+3} = \frac{-(x+3)}{x+3} = -1

  • When x=3x = -3, the denominator becomes zero, leading to an undefined value, since division by zero is not allowed.

Piecewise Definition of x+3x+3\frac{|x+3|}{x+3}:

\begin{cases} 1 & \text{if } x > -3 \\ -1 & \text{if } x < -3 \end{cases}$$ And at $$x = -3$$, the function is undefined, so $$-3$$ is not included in either part of the piecewise function. ### Inclusion or Exclusion of $$-3$$: - For $$x > -3$$, the value $$1$$ is inclusive of all values greater than $$-3$$, but not $$-3$$ itself. - For $$x < -3$$, the value $$-1$$ is inclusive of all values less than $$-3$$, but $$-3$$ itself is excluded because the function is undefined there. So, $$-3$$ is **not included** in either the positive or negative case. --- Would you like more details, or do you have any questions? Here are some related questions to consider: 1. What happens if we add a constant to the denominator? 2. How do absolute value functions behave in piecewise form for different ranges? 3. Can we extend the domain of the function to include $$x = -3$$? 4. What are some applications of absolute value functions like this one? 5. How does the graph of this piecewise function look? **Tip:** Always check for points where the denominator equals zero when dealing with rational functions, as these are points of discontinuity or undefined behavior.

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Math Problem Analysis

Mathematical Concepts

Absolute Value Functions
Piecewise Functions
Discontinuity in Rational Functions

Formulas

|x + 3| for Absolute Value Function
Piecewise Definition of Rational Functions: f(x) = {1 if x > -3, -1 if x < -3}
Undefined Behavior at x = -3 due to division by zero

Theorems

Discontinuity at points where the denominator equals zero

Suitable Grade Level

Grades 10-12