Math Problem Statement
|x+3|/(x+3) for this piecewise, how do i know which one is inclusive -3 and thenone which is not inclusive
Solution
The expression can be analyzed by determining the behavior of the absolute value function based on the value of . This will help us write the piecewise function and determine where to include or exclude specific points.
1. Behavior of :
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When (i.e., ), . In this case, the expression simplifies as:
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When (i.e., ), . In this case, the expression becomes:
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When , the denominator becomes zero, leading to an undefined value, since division by zero is not allowed.
Piecewise Definition of :
\begin{cases} 1 & \text{if } x > -3 \\ -1 & \text{if } x < -3 \end{cases}$$ And at $$x = -3$$, the function is undefined, so $$-3$$ is not included in either part of the piecewise function. ### Inclusion or Exclusion of $$-3$$: - For $$x > -3$$, the value $$1$$ is inclusive of all values greater than $$-3$$, but not $$-3$$ itself. - For $$x < -3$$, the value $$-1$$ is inclusive of all values less than $$-3$$, but $$-3$$ itself is excluded because the function is undefined there. So, $$-3$$ is **not included** in either the positive or negative case. --- Would you like more details, or do you have any questions? Here are some related questions to consider: 1. What happens if we add a constant to the denominator? 2. How do absolute value functions behave in piecewise form for different ranges? 3. Can we extend the domain of the function to include $$x = -3$$? 4. What are some applications of absolute value functions like this one? 5. How does the graph of this piecewise function look? **Tip:** Always check for points where the denominator equals zero when dealing with rational functions, as these are points of discontinuity or undefined behavior.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Absolute Value Functions
Piecewise Functions
Discontinuity in Rational Functions
Formulas
|x + 3| for Absolute Value Function
Piecewise Definition of Rational Functions: f(x) = {1 if x > -3, -1 if x < -3}
Undefined Behavior at x = -3 due to division by zero
Theorems
Discontinuity at points where the denominator equals zero
Suitable Grade Level
Grades 10-12