Math Problem Statement

find the phasor notation of the following time-harmonic vectors: a. V(t) = 3cos(wt)x + 4sin(wt)y + zcos(wt + pi/2)

Solution

To find the phasor notation for the given time-harmonic vector:

V(t)=3cos(ωt)x^+4sin(ωt)y^+cos(ωt+π2)z^V(t) = 3\cos(\omega t) \hat{x} + 4\sin(\omega t) \hat{y} + \cos(\omega t + \frac{\pi}{2}) \hat{z}

Step-by-Step Solution:

  1. Express the components in terms of cosines:

    Recall the following trigonometric identity for sine in terms of cosine: sin(ωt)=cos(ωtπ2)\sin(\omega t) = \cos\left(\omega t - \frac{\pi}{2}\right) So, we can rewrite the components of the vector in cosine form:

    • For the x^\hat{x}-component, 3cos(ωt)3 \cos(\omega t) is already in cosine form, so it remains as is.

    • For the y^\hat{y}-component, 4sin(ωt)4 \sin(\omega t) becomes: 4sin(ωt)=4cos(ωtπ2)4 \sin(\omega t) = 4 \cos\left(\omega t - \frac{\pi}{2}\right)

    • For the z^\hat{z}-component, cos(ωt+π2)\cos(\omega t + \frac{\pi}{2}) can be rewritten using the phase-shift identity: cos(ωt+π2)=sin(ωt)=cos(ωtπ2)\cos(\omega t + \frac{\pi}{2}) = -\sin(\omega t) = -\cos\left(\omega t - \frac{\pi}{2}\right)

  2. Represent the components in phasor form:

    The phasor notation involves converting the time-dependent cosines into complex exponentials. A general cosine term Acos(ωt+ϕ)A \cos(\omega t + \phi) can be represented as a phasor: AϕA \angle \phi Where AA is the amplitude and ϕ\phi is the phase shift.

    Now, we convert each term:

    • The x^\hat{x}-component: 3cos(ωt)3 \cos(\omega t) corresponds to a phasor 303 \angle 0^\circ.

    • The y^\hat{y}-component: 4cos(ωtπ2)4 \cos(\omega t - \frac{\pi}{2}) corresponds to a phasor 4904 \angle -90^\circ.

    • The z^\hat{z}-component: cos(ωtπ2)-\cos(\omega t - \frac{\pi}{2}) corresponds to a phasor 190-1 \angle -90^\circ, which is equivalent to a phasor with amplitude 1 and phase 90-90^\circ.

Final Phasor Representation:

Now we can write the phasor notation for the vector V(t)V(t) as:

V=30x^+490y^190z^V = 3 \angle 0^\circ \hat{x} + 4 \angle -90^\circ \hat{y} - 1 \angle -90^\circ \hat{z}

This is the phasor form of the given time-harmonic vector.


Would you like further explanation or assistance with any other problem?

Related Questions:

  1. How do you convert a sine function to its phasor form?
  2. How do you express a vector in terms of its real and imaginary parts in phasor notation?
  3. What is the meaning of a phase shift in phasor notation?
  4. How do you add multiple phasors together?
  5. What is the difference between complex exponential representation and phasor representation?

Tip:

When working with phasors, remember that the phasor represents the amplitude and phase of a cosine function. By using Euler’s formula, you can relate a cosine term to its complex exponential equivalent.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Phasor Notation
Time-Harmonic Vectors
Trigonometric Identities
Cosine and Sine Functions

Formulas

A cos(ωt + φ) = A ∠φ
sin(ωt) = cos(ωt - π/2)
cos(ωt + π/2) = -sin(ωt)

Theorems

Phasor Representation
Trigonometric Identities

Suitable Grade Level

Grades 11-12