Math Problem Statement

A pair of sine curves with the same period is given.

y1 = 20 sin2t βˆ’

πœ‹

6

;    y2 = 20 sin2t βˆ’

7πœ‹

6

(a) Find the phase of each curve.

y1 phase

y2 phase

(b) Find the phase difference between the curves.

(c) Determine whether the curves are in phase or out of phase.

in phaseout of phase

Solution

We are given two sine curves with the following equations:

y1=20sin⁑(2tβˆ’Ο€6)y_1 = 20 \sin(2t - \frac{\pi}{6}) y2=20sin⁑(2tβˆ’7Ο€6)y_2 = 20 \sin(2t - \frac{7\pi}{6})

(a) Find the phase of each curve

The general form of a sine function is:

y=Asin⁑(Btβˆ’Ο•)y = A \sin(Bt - \phi)

Where:

  • AA is the amplitude,
  • BB is the angular frequency (related to the period),
  • Ο•\phi is the phase angle (or phase shift).

For the two curves, the phase angle Ο•\phi is given by the term subtracted from 2t2t.

  1. Phase of y1y_1: The phase of y1=20sin⁑(2tβˆ’Ο€6)y_1 = 20 \sin(2t - \frac{\pi}{6}) is Ο€6\frac{\pi}{6}.
  2. Phase of y2y_2: The phase of y2=20sin⁑(2tβˆ’7Ο€6)y_2 = 20 \sin(2t - \frac{7\pi}{6}) is 7Ο€6\frac{7\pi}{6}.

(b) Find the phase difference between the curves

The phase difference Δϕ\Delta \phi between the two curves is the difference between the two phase angles:

Δϕ=∣7Ο€6βˆ’Ο€6∣\Delta \phi = \left| \frac{7\pi}{6} - \frac{\pi}{6} \right|

Δϕ=6Ο€6=Ο€\Delta \phi = \frac{6\pi}{6} = \pi

(c) Determine whether the curves are in phase or out of phase

The curves are out of phase if the phase difference is not zero. In this case, the phase difference is Ο€\pi, which means the two sine waves are completely out of phase (they are 180 degrees apart). This means when one sine wave reaches its peak, the other is at its trough.

Summary of Results:

  • (a) Phase of y1y_1: Ο€6\frac{\pi}{6}
  • (a) Phase of y2y_2: 7Ο€6\frac{7\pi}{6}
  • (b) Phase difference: Ο€\pi
  • (c) The curves are out of phase.

Do you want more details on phase shifts or have any questions? Here are five related questions to expand this topic:

  1. How does the period of a sine wave relate to its angular frequency?
  2. What happens to the phase shift if we increase the constant in the sine argument?
  3. Can two sine waves with the same frequency ever be in phase if their phase difference is Ο€/2\pi/2?
  4. What is the meaning of amplitude in the sine wave equations?
  5. How does changing the amplitude affect the graph of a sine curve?

Tip: The phase difference of Ο€\pi (180 degrees) between two sine waves means they will cancel each other out if added, leading to destructive interference.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Sine Waves
Phase Difference

Formulas

y = A sin(Bt βˆ’ Ο•)
Phase difference Δϕ = |Ο•2 βˆ’ Ο•1|

Theorems

Phase Shift Theorem

Suitable Grade Level

Grades 10-12