Math Problem Statement

MicroCorp will hold its annual company picnic next week and will assign 3 planning duties to its employees. One person selected will reserve a venue, another will arrange catering, and a third will plan activities. There are 10 employees eligible to fulfill these duties, and no employee can be assigned more than one duty. How many different ways are there for duties to be assigned to employees?

Solution

To determine the number of ways the three planning duties can be assigned to the employees, we use the permutation rule, since the order in which the duties are assigned matters.

Step-by-Step Solution:

  1. Select an employee for the first duty (reserving a venue): There are 10 eligible employees. Thus, there are 10 choices for the first duty.

  2. Select an employee for the second duty (arranging catering): After the first employee has been assigned, there are 101=910 - 1 = 9 remaining employees. Thus, there are 9 choices for the second duty.

  3. Select an employee for the third duty (planning activities): After the first two employees have been assigned, there are 102=810 - 2 = 8 remaining employees. Thus, there are 8 choices for the third duty.

  4. Calculate the total number of permutations: Multiply the number of choices for each duty: Total number of ways=10×9×8=720\text{Total number of ways} = 10 \times 9 \times 8 = 720

Final Answer:

There are 720 different ways to assign the duties to the employees.


Would you like me to go over the concept of permutations or provide another example? 😊

Related Questions:

  1. What if there were 15 employees instead of 10? How many ways would the duties be assigned?
  2. How does this problem differ if the order of duties does not matter?
  3. If one specific employee must reserve the venue, how many ways can the remaining duties be assigned?
  4. What formula is generally used to calculate permutations?
  5. Can this problem be solved using a combination instead of a permutation? Why or why not?

Tip:

When deciding between permutations and combinations, remember that permutations account for order, while combinations do not.

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Math Problem Analysis

Mathematical Concepts

Permutations
Counting Principles
Combinatorics

Formulas

P(n, r) = n × (n-1) × ... × (n-r+1)
General counting principle for sequential choices

Theorems

Permutation theorem

Suitable Grade Level

Grades 9-12