Math Problem Statement

12P6

Solution

The notation 12P6{}^{12}P_6 represents a permutation, which is calculated using the formula:

nPr=n!(nr)!{}^nP_r = \frac{n!}{(n - r)!}

Substituting n=12n = 12 and r=6r = 6:

12P6=12!(126)!=12!6!{}^{12}P_6 = \frac{12!}{(12-6)!} = \frac{12!}{6!}

Expanding factorials:

12!6!=12×11×10×9×8×7×6!6!\frac{12!}{6!} = \frac{12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6!}{6!}

Cancel 6!6! in the numerator and denominator:

12×11×10×9×8×7=66528012 \times 11 \times 10 \times 9 \times 8 \times 7 = 665280

Thus, the final answer is:

665280\mathbf{665280}

Would you like a step-by-step explanation or more details?

Here are five related questions for further exploration:

  1. What is the difference between permutations and combinations?
  2. How do you calculate nPr{}^{n}P_{r} when given different values of nn and rr?
  3. How does factorial notation work, and why is it used in permutations?
  4. Can you explain an application of permutations in real life?
  5. How would you calculate 12C6{}^{12}C_6, which represents combinations instead of permutations?

Tip: In permutations, the order matters, while in combinations, it does not.

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Math Problem Analysis

Mathematical Concepts

Permutations
Factorials
Combinatorics

Formulas

^nP_r = n! / (n - r)!

Theorems

Permutation formula

Suitable Grade Level

Grades 9-12