Math Problem Statement

Consider the signal x(t) = 4 cos  2π 3 t + π 3  . (a) What is the period of this signal? (b) What is the value of this signal at t = 0, i.e., what is x(0)? (c) Plot the signal

Solution

Here is the plot of the signal x(t)=4cos(2π13t+π3)x(t) = 4 \cos \left( 2\pi \frac{1}{3} t + \frac{\pi}{3} \right), showing its oscillation over time. You can observe the periodic nature of the signal, with a period of 3 seconds, as calculated earlier.

Would you like more details on any part of the solution, or do you have any questions?

Here are 5 related questions that expand on this concept:

  1. How would the period of the signal change if the frequency were doubled?
  2. What would the plot look like if the phase shift were π2\frac{\pi}{2} instead of π3\frac{\pi}{3}?
  3. How do you determine the amplitude of a cosine signal from its equation?
  4. How does adding a sine component to the signal change its behavior?
  5. What is the relationship between frequency and angular velocity in a cosine signal?

Tip: In periodic signals, the phase shift ϕ\phi affects the horizontal translation but doesn't change the signal's frequency or amplitude.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Signal Processing
Cosine Functions
Periodic Functions

Formulas

Cosine function: x(t) = A cos(ωt + φ)
Period: T = 2π/ω

Theorems

Periodicity of cosine functions
Phase shift in trigonometric functions

Suitable Grade Level

Grades 10-12