Math Problem Statement

Consider the following. y = 12 cos

𝜋x/ 4

Find the period and the amplitude of the graph of the function. period

Correct: Your answer is correct. Nice work! amplitude

Correct: Your answer is correct. Nice job! Consider one period beginning on the y-axis. Determine the five distinct key points (intercepts, maximum points, and minimum points) in this period. Intercepts smallest x-value (x, y)

Incorrect: Your answer is incorrect.

(x, y)

Incorrect: Your answer is incorrect.

largest x-value (x, y)

Incorrect: Your answer is incorrect.

Maximum and Minimum Points maximum (x, y)

Incorrect: Your answer is incorrect.

minimum (x, y)

Solution

Let's break down the function y=12cos(πx4)y = 12 \cos\left( \frac{\pi x}{4} \right) to determine the key points over one period.

1. Amplitude and Period

  • The amplitude is the coefficient of the cosine function, which is 1212. So, the amplitude is 1212.
  • The period is calculated using the formula:

Period=2πB\text{Period} = \frac{2\pi}{B} Where BB is the coefficient of xx inside the cosine. In this case, B=π4B = \frac{\pi}{4}. Thus:

Period=2ππ4=8\text{Period} = \frac{2\pi}{\frac{\pi}{4}} = 8

2. Key Points of One Period

Cosine functions have 5 key points over one period: starting at a maximum, passing through intercepts (where y=0y = 0), reaching a minimum, and returning to the maximum. For cos(πx4)\cos\left(\frac{\pi x}{4}\right), let's calculate the key points.

  • The general cosine function starts at x=0x = 0 (maximum), reaches zero at 14\frac{1}{4} of the period, minimum at 12\frac{1}{2} of the period, zero again at 34\frac{3}{4} of the period, and maximum at the end of the period.

Given that the period is 8, the key points occur at:

  • Start (Maximum): At x=0x = 0, y=12y = 12. (x,y)=(0,12)(x, y) = (0, 12)
  • First Intercept: At x=2x = 2, y=0y = 0. (x,y)=(2,0)(x, y) = (2, 0)
  • Minimum: At x=4x = 4, y=12y = -12. (x,y)=(4,12)(x, y) = (4, -12)
  • Second Intercept: At x=6x = 6, y=0y = 0. (x,y)=(6,0)(x, y) = (6, 0)
  • End (Maximum): At x=8x = 8, y=12y = 12. (x,y)=(8,12)(x, y) = (8, 12)

Summary of Key Points

  • Maximum: (0,12)(0, 12)
  • First intercept: (2,0)(2, 0)
  • Minimum: (4,12)(4, -12)
  • Second intercept: (6,0)(6, 0)
  • Maximum again: (8,12)(8, 12)

Incorrect Answers

Your previously marked incorrect points were likely due to incorrect xx-values or yy-values at these key points. With these corrected key points, you should have the proper intercepts and extrema.


Would you like further details on this solution, or do you have any questions?

Related Questions:

  1. How do we determine the phase shift in cosine functions?
  2. Can you explain how transformations like vertical shifts affect key points?
  3. What is the significance of the period in oscillating functions?
  4. How would the key points change if the function was y=12cos(πx4)y = -12 \cos\left(\frac{\pi x}{4}\right)?
  5. How do we graph the function using the key points?

Tip: In trigonometric functions, always confirm the period and amplitude before plotting or calculating key points!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Graphing Trigonometric Functions
Amplitude
Period

Formulas

Period = 2π / B
Amplitude = |A|

Theorems

Cosine Function Properties

Suitable Grade Level

Grades 10-12