Consider the following.
y = 12 cos

𝜋x/
4

Find the period and the amplitude of the graph of the function.
period	
  
Correct: Your answer is correct.
 Nice work!
amplitude	
  
Correct: Your answer is correct.
 Nice job!
Consider one period beginning on the y-axis. Determine the five distinct key points (intercepts, maximum points, and minimum points) in this period.
Intercepts
smallest x-value	
(x, y)
= 

  
Incorrect: Your answer is incorrect.
 

(x, y)
= 

  
Incorrect: Your answer is incorrect.
 

largest x-value	
(x, y)
= 

  
Incorrect: Your answer is incorrect.
 

Maximum and Minimum Points
maximum	
(x, y)
= 

  
Incorrect: Your answer is incorrect.
 

minimum	
(x, y)
= 


Let's break down the function \( y = 12 \cos\left( \frac{\pi x}{4} \right) \) to determine the key points over one period.

### 1. **Amplitude and Period**

- The **amplitude** is the coefficient of the cosine function, which is \( 12 \). So, the amplitude is \( 12 \).
- The **period** is calculated using the formula:

\[
\text{Period} = \frac{2\pi}{B}
\]
Where \( B \) is the coefficient of \( x \) inside the cosine. In this case, \( B = \frac{\pi}{4} \). Thus:

\[
\text{Period} = \frac{2\pi}{\frac{\pi}{4}} = 8
\]

### 2. **Key Points of One Period**

Cosine functions have 5 key points over one period: starting at a maximum, passing through intercepts (where \( y = 0 \)), reaching a minimum, and returning to the maximum. For \( \cos\left(\frac{\pi x}{4}\right) \), let's calculate the key points.

- The general cosine function starts at \( x = 0 \) (maximum), reaches zero at \( \frac{1}{4} \) of the period, minimum at \( \frac{1}{2} \) of the period, zero again at \( \frac{3}{4} \) of the period, and maximum at the end of the period.
  
Given that the period is 8, the key points occur at:

- **Start (Maximum)**: At \( x = 0 \), \( y = 12 \).
  \[
  (x, y) = (0, 12)
  \]
- **First Intercept**: At \( x = 2 \), \( y = 0 \).
  \[
  (x, y) = (2, 0)
  \]
- **Minimum**: At \( x = 4 \), \( y = -12 \).
  \[
  (x, y) = (4, -12)
  \]
- **Second Intercept**: At \( x = 6 \), \( y = 0 \).
  \[
  (x, y) = (6, 0)
  \]
- **End (Maximum)**: At \( x = 8 \), \( y = 12 \).
  \[
  (x, y) = (8, 12)
  \]

### Summary of Key Points

- **Maximum**: \( (0, 12) \)
- **First intercept**: \( (2, 0) \)
- **Minimum**: \( (4, -12) \)
- **Second intercept**: \( (6, 0) \)
- **Maximum again**: \( (8, 12) \)

### Incorrect Answers

Your previously marked incorrect points were likely due to incorrect \( x \)-values or \( y \)-values at these key points. With these corrected key points, you should have the proper intercepts and extrema.

---

Would you like further details on this solution, or do you have any questions?

### Related Questions:
1. How do we determine the phase shift in cosine functions?
2. Can you explain how transformations like vertical shifts affect key points?
3. What is the significance of the period in oscillating functions?
4. How would the key points change if the function was \( y = -12 \cos\left(\frac{\pi x}{4}\right) \)?
5. How do we graph the function using the key points?

**Tip**: In trigonometric functions, always confirm the period and amplitude before plotting or calculating key points!

Consider the following. y = 12 cos(πx / 4). Find the period and the amplitude of the graph of the function. Consider one period beginning on the y-axis. Determine the five distinct key points (intercepts, maximum points, and minimum points) in this period.

Explore how to find the period and amplitude of the trigonometric function y = 12 cos(πx / 4) and determine the five key points (intercepts, maximum, and minimum) within one period. Ideal for high school students studying trigonometry (Grades 10-12).

Math Problem Statement

Correct: Your answer is correct. Nice job! Consider one period beginning on the y-axis. Determine the five distinct key points (intercepts, maximum points, and minimum points) in this period. Intercepts smallest x-value (x, y)

(x, y)

largest x-value (x, y)

Maximum and Minimum Points maximum (x, y)

minimum (x, y)

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