To find the perimeter of the floor in the scale drawing, we first determine the scale factor.

Step 1: Find the Scale Factor

The actual length of the floor is 30 feet, and its corresponding length in the drawing is 10 inches.
Since 1 foot = 12 inches, we convert 30 feet to inches:

$30 \times 12 = 360 \text{ inches}$

Now, we calculate the scale factor:

$\frac{10 \text{ inches}}{360 \text{ inches}} = \frac{1}{36}$

So, the scale factor is 1:36.

Step 2: Find the Width in the Scale Drawing

The actual width of the classroom is 33 feet, which in inches is:

$33 \times 12 = 396 \text{ inches}$

Using the scale factor:

$\frac{396}{36} = 11 \text{ inches}$

Step 3: Find the Perimeter in the Scale Drawing

The perimeter of a rectangle is given by:

$P = 2(\text{length} + \text{width})$

Substituting the scaled values:

$P = 2(10 + 11) = 2(21) = 42 \text{ inches}$

Thus, the perimeter of the floor in the scale drawing is 42 inches.

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Do you want more details or have any questions?

Here are 5 related problems you might find interesting:

1. If the scale drawing had a width of 8 inches, what would the actual width of the classroom be?
2. What is the area of the classroom floor in square feet and in square inches?
3. How would the perimeter change if the scale factor were 1:24 instead?
4. If a different classroom had a scale length of 12 inches, what would be its actual length given the same scale factor?
5. What is the diagonal length of the classroom in feet and in inches?

Tip:

When working with scale drawings, always ensure that both dimensions (length and width) follow the same scale factor to avoid distortions in calculations.