A eat 25% more than B. C eats 40% less than A. If all ate total 30 kg. Then how much B ate?

Let the amount of food that B eats be denoted as \( x \) kg.

### Step-by-step breakdown:

1. **A eats 25% more than B**:  
   So, A eats \( 1.25x \) kg.

2. **C eats 40% less than A**:  
   That means C eats \( 0.6 \times 1.25x = 0.75x \) kg.

3. **The total amount of food eaten is 30 kg**:  
   Therefore, the sum of the food eaten by A, B, and C is:
   \[
   x + 1.25x + 0.75x = 30
   \]
   
4. **Simplifying the equation**:
   \[
   x + 1.25x + 0.75x = 30
   \]
   \[
   3x = 30
   \]
   
5. **Solving for \( x \)**:
   \[
   x = \frac{30}{3} = 10
   \]

Thus, B ate **10 kg** of food.

Would you like further details or have any questions?

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Here are 5 related questions to expand on this concept:
1. If B ate 10 kg, how much did A eat?
2. How much did C eat in this scenario?
3. What percentage of the total food did B eat?
4. If the total amount eaten increased to 36 kg, how much would B have eaten?
5. What if A ate 50% more than B instead of 25%, how much would B have eaten?

**Tip**: When dealing with percentage increases or decreases, converting them into fractions helps simplify equations.

A eats 25% more than B. C eats 40% less than A. If all ate a total of 30 kg, how much did B eat?

Solve a percentage comparison problem where A eats 25% more than B, and C eats 40% less than A. Given that the total amount eaten is 30 kg, find out how much B ate using basic algebra and percentage formulas. Suitable for Grades 6-8.

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