Math Problem Statement

A movie club surveyed 300 high school students. The students were asked how often they go to the movies and whether they prefer action movies or comedies. The data is summarized in a table. (a) What percentage of the students go to the movies three times a month or more? (b) What percentage of the students prefer action movies?

Solution

Let's solve the questions based on the data provided in the table:


(a) Percentage of students who go to the movies three times a month or more

  • Total number of students who go three times a month or more = 51+45=9651 + 45 = 96.
  • Total number of surveyed students = 300300.
  • Percentage = 96300×100=32%\frac{96}{300} \times 100 = 32\%.

(b) Percentage of students who prefer action movies

  • Total number of students who prefer action movies = 93+51=14493 + 51 = 144.
  • Total number of surveyed students = 300300.
  • Percentage = 144300×100=48%\frac{144}{300} \times 100 = 48\%.

Final Answers:

  • (a): 32%32\%
  • (b): 48%48\%

Would you like a detailed explanation of the calculations or help with any related concepts?


Here are 5 questions to expand your understanding:

  1. How would the percentages change if 50 more students were surveyed?
  2. What is the total percentage of students who prefer comedy movies?
  3. How would the analysis differ if we only considered students who attend movies twice a month or less?
  4. If 10% more students preferred action movies, what would the new percentage be?
  5. What is the ratio of action movie preferences to comedy preferences?

Tip: Always double-check your total percentages to ensure they sum up to 100% when analyzing survey data.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Percentages
Summation

Formulas

Percentage = (Part / Total) * 100

Theorems

-

Suitable Grade Level

Grades 6-8