The image asks for the area under the standard normal distribution curve between $z = -2$ and $z = 2$, and to convert that area into a percentage.

To solve this:

1. In a standard normal distribution, the total area under the curve is 1, representing 100%.
2. The area between $z = -2$ and $z = 2$ corresponds to the probability of a value falling within two standard deviations of the mean.
3. From standard normal distribution tables or a calculator, the cumulative probability for $z = 2$ is approximately 0.9772, and for $z = -2$, it is 0.0228.
4. The area between $z = -2$ and $z = 2$ is: $0.9772 - 0.0228 = 0.9544$
5. Converting this into a percentage: $0.9544 \times 100 = 95.44\%$

So, about 95.44% of the area is between $z = -2$ and $z = 2$.

Would you like more details or have any further questions?

Here are 5 related questions for further exploration:

1. What is the area under the normal curve between $z = -1$ and $z = 1$?
2. How does the empirical rule (68-95-99.7 rule) apply to normal distributions?
3. How can we calculate areas under the curve for non-standard normal distributions?
4. What is the cumulative probability for $z = 3$?
5. How would the area change if you used a different z-range, like $z = -3$ to $z = 3$?

Tip: The standard normal distribution tables can be used to find cumulative probabilities for any z-score!