Math Problem Statement
(b) Give the demand function; (10) q_1=f(p_1,p_2 )=36,000-0.1p_1^2-0.5p_2^2 Determine the partial derivatives f_(p_1 )and f_(p_2 ) If p_1=20 and p_2=10, evaluate f_(p_1 ) and f_(p_2 ) and interpret their meaning.
Solution
The demand function is given as:
We are tasked with determining the partial derivatives of with respect to and , and then evaluating them at and .
Step 1: Compute the Partial Derivatives
1. Partial Derivative with respect to :
To find , we treat as a constant and differentiate with respect to .
= -0.2p_1$$ #### 2. Partial Derivative with respect to $$p_2$$: To find $$\frac{\partial f}{\partial p_2}$$, we treat $$p_1$$ as a constant and differentiate $$f(p_1, p_2)$$ with respect to $$p_2$$. $$\frac{\partial f}{\partial p_2} = \frac{d}{dp_2} \left( 36,000 - 0.1p_1^2 - 0.5p_2^2 \right) = -p_2$$ ### Step 2: Evaluate the Partial Derivatives at $$p_1 = 20$$ and $$p_2 = 10$$ #### 1. Evaluating $$\frac{\partial f}{\partial p_1}$$ at $$p_1 = 20$$: $$\frac{\partial f}{\partial p_1} \Bigg|_{p_1=20} = -0.2(20) = -4$$ #### 2. Evaluating $$\frac{\partial f}{\partial p_2}$$ at $$p_2 = 10$$: $$\frac{\partial f}{\partial p_2} \Bigg|_{p_2=10} = -(10) = -10$$ ### Interpretation of the Results: 1. **$$\frac{\partial f}{\partial p_1} = -4$$** means that when $$p_1 = 20$$, for each unit increase in $$p_1$$, the demand $$q_1$$ decreases by approximately 4 units, holding $$p_2$$ constant. This reflects the **rate of change of demand with respect to the price $$p_1$$**. 2. **$$\frac{\partial f}{\partial p_2} = -10$$** means that when $$p_2 = 10$$, for each unit increase in $$p_2$$, the demand $$q_1$$ decreases by approximately 10 units, holding $$p_1$$ constant. This reflects the **rate of change of demand with respect to the price $$p_2$$**. These partial derivatives indicate how sensitive the demand $$q_1$$ is to changes in $$p_1$$ and $$p_2$$, showing that demand decreases with increases in either price. --- Would you like further details on these calculations, or do you have any other questions? ### Related Questions: 1. What does a positive partial derivative signify in a demand function? 2. How can second-order partial derivatives help in understanding concavity or convexity of demand functions? 3. What is the interpretation of cross-partial derivatives in multivariable functions? 4. How does elasticity of demand relate to the partial derivatives of the demand function? 5. How would changes in prices $$p_1$$ and $$p_2$$ affect total revenue based on these partial derivatives? ### Tip: When interpreting partial derivatives in economics, think of them as marginal effects—how a small change in one variable impacts the outcome, holding other variables constant.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Multivariable Calculus
Partial Derivatives
Economic Demand Functions
Formulas
f(p1, p2) = 36,000 - 0.1p1^2 - 0.5p2^2
Partial Derivative: ∂f/∂p1 = -0.2p1
Partial Derivative: ∂f/∂p2 = -p2
Theorems
Partial Derivative Theorem
Marginal Analysis in Economics
Suitable Grade Level
Undergraduate Economics or Calculus
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