Math Problem Statement
p = f(x) = −0.1x2 − 0.3x + 30 where x is the quantity demanded in thousands and p is the unit price in dollars. (a) Find f '(x). f '(x) =
(b) What is the rate of change of the unit price (in dollars per 1,000 lamps) when the quantity demanded is 2,000 units (x = 2)? $ per 1,000 lamps What is the unit price (in dollars) at that level of demand?
Solution
Part (a): Find the derivative of
Given the function:
To find , we will differentiate each term of with respect to :
- The derivative of is (using the power rule: ).
- The derivative of is (since the derivative of is 1).
- The derivative of the constant 30 is 0 (since the derivative of a constant is always 0).
Thus, the derivative is:
Part (b): Rate of change when
To find the rate of change when the quantity demanded is 2,000 units (which corresponds to because the units are in thousands), we will substitute into the derivative .
Substituting into :
Thus, the rate of change of the unit price when the quantity demanded is 2,000 units is dollars per 1,000 lamps. This means the price decreases by $0.70 for each additional 1,000 lamps demanded.
Unit price at
To find the unit price at , we substitute into the original price function :
Thus, the unit price when the quantity demanded is 2,000 units is $29.
Summary of Answers:
- (a)
- (b) The rate of change of the unit price at is dollars per 1,000 lamps.
- The unit price at (2,000 units) is $29.
Let me know if you'd like more details or have further questions!
Related Questions:
- What happens to the rate of change of price if increases further (e.g., at )?
- How does the rate of change of price impact a firm's pricing strategy in real-life scenarios?
- What would be the price when the demand is at 1,000 units ()?
- How can the second derivative help analyze the concavity of the price function?
- If the price increases by $0.70 per 1,000 units, what effect would that have on total revenue?
Tip: When interpreting the rate of change in a function like this, think of it as a slope that tells you how much the price will increase or decrease as demand changes.
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Math Problem Analysis
Mathematical Concepts
Differentiation
Quadratic Functions
Rate of Change
Formulas
f'(x) = d(ax^2 + bx + c)/dx = 2ax + b
f'(2) = -0.2(2) - 0.3
f(x) = ax^2 + bx + c for calculating price when demand level is known
Theorems
Power Rule for Derivatives
Linear Approximation for Rates of Change
Suitable Grade Level
Grades 10-12
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