In a parallelogram, the diagonals bisect each other. This means that point $H$, the intersection of diagonals, divides diagonal $GE$ into two equal segments: $GH$ and $HE$.

Given:

• $GH = 4 \, \text{inches}$

Since $GH = HE$, the length of $GE$ is: $GE = GH + HE = 4 + 4 = 8 \, \text{inches}$

Answer: $\mathbf{8}$ inches

---

Do you need further explanation or have additional questions? Here are some related questions to explore:

1. How do the diagonals of a parallelogram behave in terms of their bisecting properties?
2. Can you find the length of diagonal $DF$ using similar methods?
3. What are the properties of the diagonals in special parallelograms like rectangles or rhombi?
4. How does the intersection point divide the diagonals in non-parallelogram quadrilaterals?
5. How can you use the Pythagorean theorem to verify diagonal lengths in a parallelogram?

Tip: Always double-check whether a problem involves special parallelogram properties (like bisected diagonals) to simplify your calculations!